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Degger [83]
2 years ago
7

PLEASE HELPPPP !!!! Scientific investigations must be well ____ to be sure the data collected will help answer the scientists qu

estion IT IS DUE BY TOMORROW
Physics
1 answer:
konstantin123 [22]2 years ago
3 0
Answer-

Analyzed or conducted

Hope this helped
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How does amplitude determine loudness?
sdas [7]

Answer:

Explanation:

Amplitude is a measure of the size of sound waves. It depends on the amount of energy that started the waves. Greater amplitude waves have more energy and greater intensity, so they sound louder.

7 0
2 years ago
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Suppose you wish to whirl a pail full of water in a vertical circle at a constant speed without spilling any of its contents (ev
Yanka [14]

Answer:

V = 2.87 m/s

Explanation:

The minimum speed required would be that at which the acceleration due to gravity is negated by the centrifugal force on the water.

Thus, we simply need to set the centripetal acceleration equal to gravity and solve for the speed V using the following equation:

Centripetal acceleration = V^2 / r

where r is the distance of water from the pivot or shoulder.

For our case, r will be 0.65 + 0.19 = 0.84 m

and solving the above equation we get:

9.81 = V^2 / 0.84

V^2 = 8.2404

V = 2.87 m/s

6 0
2 years ago
Assume that the blocks are accelerating, and the x components of their accelerations at a certain moment are a1x and a2x. find t
Serga [27]

we know that center of mass is given as

r = (m₁ r_{1x} + m₂ r_{2x})/(m₁ + m₂)

taking derivative both side relative to "t"

dr/dt = (m₁ dr_{1x}/dt + m₂ dr_{2x}/dt)/(m₁ + m₂)

v = (m₁ v_{1x} + m₂ v_{2x})/(m₁ + m₂)

taking derivative again relative to "t" both side

dv/dt = (m₁ dv_{1x}/dt + m₂ dv_{2x}/dt)/(m₁ + m₂)

a= (m₁ a_{1x} + m₂ a_{2x})/(m₁ + m₂)

3 0
3 years ago
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If the distance between the center of two objects is quadrupled. The gravitational
Juliette [100K]

Answer:

F' = F/16

Explanation:

The gravitational force between masses is given by :

F=G\dfrac{m_1m_2}{r^2}

If the distance between the center of two objects is quadrupled, r' = 4r

New force will be :

F'=G\dfrac{m_1m_2}{r'^2}\\\\F'=G\dfrac{m_1m_2}{(4r)^2}\\\\F'=\dfrac{Gm_1m_2}{16r^2}\\\\F'=\dfrac{1}{16}\times \dfrac{Gm_1m_2}{r^2}\\\\F'=\dfrac{F}{16}

So, the new force will change by a factor of 16.

6 0
3 years ago
when an object falls to the ground, only the object moves down but the earth's motion is not noticeable​.why?
vlada-n [284]
Both the object and earth pulls each other towards itself but since the mass and pulling force of objects are very small the pulling force of objects are negligible.
7 0
2 years ago
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