-- The kinetic energy it has when it hits the ground is exactly
the potential energy it had just before you dropped it.
-- So if you want it to have twice as much kinetic energy at the bottom,
you want it to have twice as much potential energy at the top.
-- Potential energy = (mass)·(gravity)·(height).
The only one of those things that you can change is the height.
Looking at that equation, you can see that if you change the height,
the potential energy changes by the same factor.
So if you want the pebble to have twice as much potential energy,
you have to drop it from twice the original height. (2h)
Answer:
32.46m/s
Explanation:
Hello,
To solve this exercise we must be clear that the ball moves with constant acceleration with the value of gravity = 9.81m / S ^ 2
A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are the follow

Where
Vf = final speed
Vo = Initial speed
=7.3m/S
A = g=acceleration
=9.81m/s^2
X = displacement
=51m}
solving for Vf

the speed with the ball hits the ground is 32.46m/s
Answer:
180
Explanation:
Work done= Force x distance
<u>So rearrange the formula to find the force</u>
Force= Work done/distance
Force= 6/30
Force= 1/5 N or 0.2 N
Answer:
I think D am not pretty show