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3 years ago

Why do we add alcohol/ethanol to the leaf once it is boiled?

Physics

1 answer:

hichkok12 [17]3 years ago

4 0

Answer:

Complete answer: We boil the leaf in alcohol when we are checking it for starch to eradicate chlorophyll, which is the green pigment present in leaves. ... Hence to dissolve the chlorophyll or the green pigment present in the leaf we boil the leaf in alcohol when we are testing it for starch.

Hope this helps! Have a great day!

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A grey hound can run about 40/mph is it velocity,acceleration, or speed

loris [4]

Answer: Speed

Explanation:

Speed is the time it takes something to travel a certain distance. Accelaration is the rate at which an object's speed changes. Velocity is a vector of the object's speed and direction.

5 0

3 years ago

A radar station detects an airplane approaching directly from the east. At first observation, the range to the plane is 375.0 m

Gekata [30.6K]

Answer:

819.78 m

Explanation:

<u>Given:</u>

OA = range of initial position of the airplane from the point of observation = 375 m
OB = range of the final position of the airplane from the point of observation = 797 m
$\theta$ = angle of the initial position vector from the observation point = $43^\circ$
$\alpha$ = angle of the final position vector from the observation point = $123^\circ$
$\vec{AB}$ = displacement vector from initial position to the final position

A diagram has been attached with the solution in order to clearly show the position of the plane.

$\vec{OA} = OA\cos \theta \hat{i}+OA \sin \theta \hat{j}\\\Rightarrow \vec{OA} = 375\ m\cos 43^\circ \hat{i}+375\ m\sin 43^\circ \hat{j}\\\Rightarrow \vec{OA} = (274.26\ \hat{i}+255.75\ \hat{j})\ m\\\vec{OB} = OB\cos \alpha \hat{i}+OB \sin \alpha \hat{j}\\\Rightarrow \vec{OB} = 797\ m\cos 123^\circ \hat{i}+797\ m\sin 123^\circ \hat{j}\\\Rightarrow \vec{OB} = (-434.08\ \hat{i}+668.42\ \hat{j})\ m$

Displacement vector of the airplane will be the shortest line joining the initial position of the airplane to the final position of the airplane which is given by:

$\vec{AB}=\vec{OB}-\vec{OA}\\\Rightarrow \vec{AB} = (-434.08\ \hat{i}+668.42\ \hat{j})\ m-(274.26\ \hat{i}+255.75\ \hat{j})\ m\\\Rightarrow \vec{AB} = (-708.34\ \hat{i}+412.67\ \hat{j})\ m$

The magnitude of the displacement vector = $\sqrt{(-708.34)^2+(412.67)^2}\ m = 819.78\ m$

Hence, the magnitude of the displacement of the plane is 819.67 m during the period of observation.

8 0

3 years ago

Why do physicists say mass is more fundamental than weight??

fomenos

Answer:

because mass of a matter never changes

on the other hand the weight of a matter changes due to gravity

for example the

on the moon the pull of gravity is less than it is on earth so the Weight of an object will be less on the moon but the mass of it will stay the same

Explanation:

7 0

3 years ago

While in a park, you walk west for 52 m, then you walk 33.9° north of west for 44 m, and finally you walk due north for 25 m. Fi

vodka [1.7K]

Answer:

(a) Total north component = (26.89 + 25) = 51.89 metres

(b) Total west component = (-34.83 + 52) = 17.17 metres.

Explanation:

Do northwest components first.

North component = (sin 33.9 x 44) =26.89 metres.

West component = (cos 33.9 x 44) = -34.83metres.

Total west component = (-34.83 + 52) = 17.17 metres.

Total north component = (26.89 + 25) = 51.89 metres

4 0

3 years ago

Two small, identical metal balls with charges 7.0 µC and 14.0 µC are held in place 1.9 m apart. In an experiment, they are conne

Nostrana [21]

The new charge on 7.0 µC ball is 10.5 µC and the new charge on 14.0 µC ball is 10.5 µC.

The change in the electrostatic force after the experiment is 0.031 N.

The given parameters:

Charge on first metal ball, q1 = 7.0 µC
Charge on second metal ball, q2 = 14 µC
Distance between the charges, r = 1.9 m

<h3>Charge on each ball after experiment</h3>

After the experiment the charges will be at equilibrium, and the charge on each metal ball will be equal.

$Q_t = q_1 + q_2\\\\Q_t = 7 \mu C + 14 \mu C\\\\Q_t = 21 \ \mu C$

$Q_1 = Q_2 = \frac{Q_t}{2} = \frac{21 \mu C}{2} = 10.5 \ \mu C$

The new charge on 7.0 µC ball = 10.5 µC

The new charge on 14.0 µC ball = 10.5 µC

<h3>Change in electrostatic force</h3>

$F_1 = \frac{kQ_1Q_2}{r^2} \\\\F_1 = \frac{9\times 10^9}{1.9^2} (7 \times 10^{-6} \times 14 \times 10^{-6}) \ \\\\ F_1 = 0.244 \ N\\\\for \ new \ charges;\\\\F_2 = \frac{kQ_1Q_2}{r^2} \\\\F_2 = \frac{9\times 10^9}{1.9^2} (10.5 \times 10^{-6} \times 10.5 \times 10^{-6}) \ \\\\ F_2 = 0.275 \ N\\\\\Delta F = F_2 - F_2\\\\\Delta F = 0.275 \ N \ - \ 0.244 \ N\\\\\Delta F = 0.031 \ N$

Lear more about electrostatic force here: brainly.com/question/17692887

8 0

3 years ago