In the open circuit the current can not flow from one end of the power source to the other. Because of this there is no current flow, and therefore the light does not turn on.
 
        
                    
             
        
        
        
Answer:
0.2943 Nm
Explanation:
Work done is given a the product of force and diatance moved and expressed by the formula 
W=Fd 
Here W represent work, F is applied force and d is perpendicular distance
Also, we know that F=mg where m is the mass of an object and g is acceleration due to gravity. Substituting this back into the initial equation then
W=mgd
Taking acceleration due to gravity as 9.81 m/s2 and substituting mass with 0.1 kg and distance with 0.3 m then
W=0.1*9.81*0.3=0.2943 Nm
 
        
             
        
        
        
Answer:
v = 8.09   m/s
Explanation:
For this exercise we use that the work done by the friction force plus the potential energy equals the change in the body's energy.
Let's calculate the energy
        
starting point. Higher
          Em₀ = U = m gh
final point. To go down the slope
          Em_f = K = ½ m v²
The work of the friction force is
          W = fr L cos 180
to find the friction force let's use Newton's second law
Axis y
         N - W_y = 0
         N = W_y
X axis
         Wₓ - fr = ma
let's use trigonometry
         sin  θ = y / L
          sin θ = 11/110 = 0.1
          θ = sin⁻¹  0.1
           θ = 5.74º
          sin 5.74 = Wₓ / W
          cos 5.74 = W_y / W
          Wₓ = W sin 5.74
          W_y = W cos 5.74
the formula for the friction force is
          fr = μ N
          fr = μ W cos θ
Work is friction force is
          W_fr = - μ W L cos θ  
Let's use the relationship of work with energy
         W + ΔU = ΔK
          -μ mg L cos 5.74 + (mgh - 0) = 0  - ½ m v²
         v² = - 2 μ g L cos 5.74 +2 (gh)
         v² = 2gh - 2 μ gL cos 5.74
let's calculate
         v² = 2 9.8 11 - 2 0.07 9.8 110 cos 5.74
         v² = 215.6 -150.16
         v = √65.44
         v = 8.09   m/s
 
        
             
        
        
        
Here we can use coulomb's law to find the force between two charges
As per coulombs law
]tex]F = \frac{kq_1q_2}{r^2}[/tex]
here we have




now by using the above equation we have


so here the force between two charges is of above magnitude and this will be repulsive force between them as both charges are of same sign.