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3 years ago

What is the net force on this object?

Physics

2 answers:

vaieri [72.5K]3 years ago

8 0

Answer:

200 newtons

Explanation:

because the sub air that would pull the force down by all of the mass of the sub air go down by that 400 newtons there for your anwer is 200 newtons. because 600-400=200

likoan [24]3 years ago

6 0

Answer:

200N

Explanation:

The net force or resultant force on the object is obtained by adding all the forces acting on it.

In this case we have an upward force and a downward force, since they go in different directions they must have a different sign: we will define upward as positive and downward as negative:

$F_{air} = 400N$

$F_{grav}=-600N$

The sign only to indicate that they are going in opposite directions, so the resulting force:

$F=F_{air}+F_{grav}=400N+(-600N)=400N-600N=-200N$

The net force acting on the object is 200N. (downwars due to the negative sign).

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A satellite is orbiting the earth just above its surface. The centripetal force making the satellite follow a circular trajector

Pavlova-9 [17]

Answer:

$v=7905m/s$

$t=5063s$

Explanation:

A satellite is orbiting the earth just above its surface. The centripetal force making the satellite follow a circular trajectory is just its weight, so its centripetal acceleration is about 9.81 m/s2 (the acceleration due to gravity near the earth's surface). If the earth's radius is about 6370 km, how fast must the satellite be moving? How long will it take for the satellite to complete one trip around the earth?

The weight of the satellite is the centripetal force, so:

$W=mg=F_{cp}=ma_{cp}=m\frac{v^2}{r}$

Which means: $g=\frac{v^2}{r}$

We can calculate then the velocity:

$v=\sqrt{gr}=\sqrt{(9.81m/s^2)(6370000m)}=7905m/s$

For calculating how long will it take for the satellite to complete one trip around Earth we consider that the distance of the trip is the circumference of the orbit. This is calculated as $C=2\pi r$ .

Since velocity is v=d/t, we have:

$t=d/v=C/v=2\pi r/v=\frac{2\pi 6370000}{7905m/s} =5063s$

5 0

3 years ago

A stone has a mass of 100 grams and a volume of 10ml water has a density of 1 g/ml will the stone sink or float?

JulsSmile [24]

Density = Mass / Volume

Density of stone = 100 / 10 = 10 g/mL

If the density is higher than water, then the object will sink. If the density of the object is lower than water, then the object will float.

Since the density of the rock is 10g/mL and the density of the water is 1g/mL, the stone will sink.

3 0

3 years ago

Read 2 more answers

A 2.64-kg copper part, initially at 400 K, is plunged into a tank containing 4 kg of liquid water, initially at 300 K. The coppe

marin [14]

Answer:

a) $T_f=305.7049\ K$

b) $\Delta S=313.51\ J.K^{-1}$

Explanation:

Given:

mass of copper, $m_c=2.64\ kg$

initial temperature of copper, $T_{ic}=400\ K$

specific heat capacity of copper, $c_c=385\ J.kg^{-1}.K^{-1}$

mass of water, $m_w=4\ kg$

initial temperature of water, $T_{iw}=300\ K$

specific heat capacity of water, $c_w=4200\ J.kg^{-1}.K^{-1}$

<u>∵No heat is lost in the environment and the heat is transferred only between the two bodies:</u>

Heat rejected by the copper = heat absorbed by the water

$2.64\times 385\times (400-T_f)= 4\times 4200\times (T_f-300)$

$T_f=305.7049\ K$

<u>Now the amount of heat transfer:</u>

$Q=m_c.c_c.(T_{ic}-T_{f})$

$Q=2.64\times 385\times (400-305.7049)$

$Q=95841.5841\ J$

∴Entropy change

$\Delta S=\frac{dQ}{T}$

$\Delta S=\frac{95841.5841}{305.7049}$

$\Delta S=313.51\ J.K^{-1}$

5 0

4 years ago

Which stage of shock encompasses mechanical ventilation, altered level of consciousness, and profound acidosis?

bixtya [17]

Answer:

It is considered as the last phase of the shock when the patient become stupor and needs a life support of mechanical ventilation. It's called the irreversible shock as it leads to the failure of organ or a death of a patient.

Explanation:

8 0

3 years ago

Water is being heated in a closed pan on top of a range while being stirred by a paddle wheel.

BigorU [14]

Heat transfer in a closed system is the addition of changes in internal energy and the total amount of work done by it. The final energy of the system is 35.5kJ.

<h3>What is heat transfer? </h3>

Heat transfer is the transfer of heat energy due to temperature differences.

The paddle-wheel paintings are quantities of workdone, 500 N.m or 0.5kJ.

The preliminary (initial) power of the device is 10 kJ.

Total warmness transferred in the course of the method is 30 kJ

Total warmness misplaced in the course of the method to the encompassing air is 5 kJ.

The energy of the system is given as:

The energy of the system = Energy in - Energy out

The energy of the system = Initial energy + Energy transferred + Work done - Energy lost

Energy of the system = 10 + 30 + 0.5 - 5 kJ

Energy of the system = 35.5 kJ