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3 years ago

What is the net force on this object?

Physics

2 answers:

vaieri [72.5K]3 years ago

8 0

Answer:

200 newtons

Explanation:

because the sub air that would pull the force down by all of the mass of the sub air go down by that 400 newtons there for your anwer is 200 newtons. because 600-400=200

likoan [24]3 years ago

6 0

Answer:

200N

Explanation:

The net force or resultant force on the object is obtained by adding all the forces acting on it.

In this case we have an upward force and a downward force, since they go in different directions they must have a different sign: we will define upward as positive and downward as negative:

$F_{air} = 400N$

$F_{grav}=-600N$

The sign only to indicate that they are going in opposite directions, so the resulting force:

$F=F_{air}+F_{grav}=400N+(-600N)=400N-600N=-200N$

The net force acting on the object is 200N. (downwars due to the negative sign).

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discharge occurs when oppositely charged objects get close enough for the air between them to become electrically charged.

Wittaler [7]

Answer:

It does both. Once they get close enough the air does start to get charged, but then they eventually discharge when they touch.

Explanation:

4 0

3 years ago

Two ball bearings of mass m each moving in opposite directins with equal speed v collide head on with each other.predict the out

posledela

Yo sup??

since the collision is elastic therefore we can say that the two balls will then move in opposite direction.

If ball 1 was moving from east to west then after collision it will move from west to east

and if ball 2 was moving from west to east then it will start moving from east to west.

Hope this helps.

7 0

3 years ago

A dog running to the right at 4 m/s sees a ball and accelerates steadily to catch it. The dog accelerates to the right at a rate

antoniya [11.8K]

Answer:

D.-4.798m/s

Explanation:

Greetings !

Given values

$u= 4ms \\ a = 0.21ms {}^{2} \\ t = 3.8sec$

Solve for V of the given expression

Firstly, recall the velocity-time equation

$v = u + at$

plug in known values to the equation

$v = (4) + (0.21)(3.8)$

solve for final velocity

$v = 4.792ms$

Hope it helps!

6 0

1 year ago

.A hard rubber ball, released at chest height, falls to the pavement and bounces back to nearly the same height. When it is in c

ohaa [14]

Answer:

a = 1.1 10⁵ m / s²

Explanation:

This is a momentum exercise, where we use the relationship between momentum and momentum

I = ∫ F dt = Δp

= p_f - p₀

as they indicate that the ball bounces at the same height, we can assume that the moment when it reaches the ground is equal to the moment when it bounces, but in the opposite direction

F t = 2 (m v)

therefore the average force is

F = 2 m v / t

where in general the mass of the ball unknown, the velocity of the ball can be calculated using the conservation of energy

starting point. Done the ball is released with zero initial velocity

Em₀ = U = mgh

final point. Upon reaching the ground, just before the deformation begins

Em_f = K = ½ m v²

energy is conserved in this system

Em₀ = Em_f

m g h = ½ m v²

v = √ (2gh)

This is the velocity of the body when it reaches the ground, so the force remains

F = 2m √(2gh) /t

where the height of the person's chest is known and the time that the impact with the floor lasts must be estimated in general is of the order of milli seconds

knowing this force let's use Newton's second law

F = m a

a = F / m

a = 2 √(2gh) / t

We can estimate the order of magnitude of this acceleration, assuming the person's chest height of h = 1.5 m and a collision time of t = 1 10⁻³ s

a = 2 √ (2 9.8 1.5) / 10⁻³

a = 1.1 10⁵ m / s²

6 0

3 years ago

How much current is in a circult that includes a 9.0-volt battery and a bulb with a resistance of 4.0 ohms?

SVETLANKA909090 [29]

Answer:

Current, I = 2.3 A

Explanation:

We have,

Voltage of the battery in a circuit is 9 volts

Resistance of the circuit is 4 ohms

It is required to find the current in a circuit. When the voltage and the resistance of the circuit is given then we can find the current in it is given by Ohm's law as :

$V=IR$

I is electric current

$I=\dfrac{V}{R}\\\\I=\dfrac{9}{4}\\\\I=2.25\ A$

I = 2.3 A

So, the current in the circuit is 2.3 A.

6 0

3 years ago