Question

Suppose a treadmill has an average acceleration of 4.7 x 10^-3. A) how much does its speed change after five min? B )If the treadmill's initial speed is 1.7 m/s ,what will it's final speed be?

Answer 1

Explanation:

Given that,

Acceleration of the treadmill, $a=4.7\times 10^{-3}\ m/s^2$

Time, t = 5 min = 300 s

Acceleration is given by :

$a=\dfrac{v-u}{t}$

(a) (v-u) is the change in speed.

$v-u=a\times t$

$v-u=4.7\times 10^{-3}\times 300$  

$v-u=1.41\ m/s$

So, the change in speed of the treadmill is 1.41 m/s.      

(b) Initial speed of the treadmill, u = 1.7 m/s

The final speed is given by using equation as :

$v=u+at$

$v=1.7+4.7\times 10^{-3}\times 300$

v = 3.11 m/s

Hence, this is the required solution.

Answer 2

V1 - v0  = at

= 4.7  x 10^3 m/s^2 x 300s

= 1.4 x 10^6 m/s

hope this helps