The final temperature of the water : <u>31.916 °C</u>
<h3>Further explanation
</h3>
The law of conservation of energy can be applied to heat changes, i.e. the heat received / absorbed is the same as the heat released
Q in = Q out
Heat can be calculated using the formula:
<h3>Q = mc∆T
</h3>
Q = heat, J
m = mass, g
c = specific heat, joules / g ° C
∆T = temperature difference, ° C / K
From reaction:
2C₆H₆ (l) + 15O₂ (g) ⟶12CO₂ (g) + 6H₂O (l) +6542 kJ, heat released by +6542 kJ to burn 2 moles of C₆H₆
If there are 6,200 g of C₆H₆ then the number of moles:
mol = mass: molar mass C₆H₆
mol = 6.2: 78
mol C6H6 = 0.0795
so the heat released in combustion 0.0795 mol C6H6:
the heat produced from the burning is added to 5691 g of water at 21 ∘ C
So :
Q = m . c . ∆T (specific heat of water = 4,186 joules / gram ° C)
260044.5 = 5691 . 4.186.∆T
<h3>Learn more </h3>
the difference between temperature and heat
brainly.com/question/3821712
Specific heat
brainly.com/question/9525136
relationships among temperature, heat, and thermal energy.
brainly.com/question/224374
When heat is added to a substance
brainly.com/question/3417580