Answer:
The entropy change in the environment is 3.62x10²⁶.
Explanation:
The entropy change can be calculated using the following equation:
Where:
Q: is the energy transferred = 5.0 MJ
: is the Boltzmann constant = 1.38x10⁻²³ J/K
: is the initial temperature = 1000 K
: is the final temperature = 500 K
Hence, the entropy change is:
Therefore, the entropy change in the environment is 3.62x10²⁶.
I hope it helps you!
Some similarities between deserts and rainforests are that they support complex ecosystems, are powered by the sun/photosynthetic plants, are dangerous/mostly uninhabitable for humans, due to both conditions and wildlife, and are found mostly in the tropics
Answer:
random internal motion of atoms and molecule
Explanation:
The primary cause of diffusion is the random internal motion of atoms and molecules.
Randomness of atoms and molecules results in diffusion.
- Diffusion is the movement of particles from a region of high concentration to that of lower concentration.
- Substances often tend to spread out over the concentration gradient.
- Therefore, they have this propensity to be randomized.
Answer:
B. Distributed over a very wide range
D. Limited life existence in geologic time.
Explanation:
Index fossils are very unique fossils that helps in determining the relative ages of rocks and biostratigraphic correlation. They are usually called guide fossils.
- Fossils are the preserved remains of dead organisms found in rocks.
- Index fossils are a special class of fossils with the following properties;
- They are widely distributed.
- They have a short stratigraphic range.
- They show rapid evolution trends
Answer:
pH = 12.80
[H3O+] = 1.58 * 10^-13 M
[OH-] = 0.063 M
Explanation:
Step 1: Data given
pOH = 1.20
Temperature = 25.0 °C
Step 2: Calulate pH
pH + pOH = 14
pH = 14 - pOH
pH = 14 - 1.20 = 12.80
Step 3: Calculate hydronium ion concentration
pH = -log[H+] = -log[H3O+]
12.80 = -log[H3O+]
10^-12.80 = [H3O+] = 1.58 * 10^-13 M
Step 4: Calculate the hydroxide ion concentration
pOH = 1.20 = -log [OH-]
10^-1.20 = [OH-] = 0.063M
Step 5: Control [H3O+] and [OH-]
[H3O+]*[OH-] = 1* 10^-14
1.58 *10^-13 * 0.063 = 1* 10^-14
