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Fudgin [204]
3 years ago
10

A 45.0 kg ice skater stands at rest on the ice. A friend tosses the skater a 5.0 kg ball. The skater and the ball then move back

wards across the ice with a speed of 0.5 m/s. What was the speed of the ball at the moment just before the skater caught it?
Physics
1 answer:
Allushta [10]3 years ago
0 0

Answer:

u = 5 m/s

Explanation:

given,

Mass of ice skater, M = 45 Kg

initial speed = 0 m/s

mass of the ball, m = 5 Kg

velocity of skater and the ball,V = 0.5 m/s

speed of the ball = ?

using conservation of momentum

m u + M u' =( M + m ) V

initial speed of ice skater is zero

5 x u + 45 x 0 =( 45 + 5 ) V

5 u = 50 x 0.5

5 u = 25

u = 5 m/s

hence, the speed of the ball is equal to 5 m/s

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A solid concrete block weighs 150. N and is resting on the ground. Its dimensions are 0.400 m ✕ 0.200 m ✕ 0.100 m. A number of i
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Answer:

27 blocks

Explanation:

First, the expression to use here is the following:

P = F/A

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P: pressure

F: Force exerted

A: Area of the block.

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P = W/A

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n would be the number of blocks, and W1 the weight of the block.We have all the data, and we need to calculate the area of the block which is:

A = 0.2 * 0.1 = 0.02 m²

Solving now for n:

n = P * A / W1

The pressure has to be expressed in N/m²

P = 2 atm * 1.01x10^5 N/m² atm = 2.02x10^5 N/m²

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5 0
3 years ago
What are the coefficients in this expression?
skad [1K]

6 and \frac{1}{3}

Explanation:

The expression:

     6a - \frac{3}{4}  + 7.5 - \frac{b}{3}

 A coefficient is a numerical constant usually placed before a variable in an expression.

They are used to multiply variables.

 Given equation is;

   6a - \frac{3}{4}  + 7.5 - \frac{b}{3}

There are two variables in this expression which are;

  a and  - b

  6 (a) - \frac{3}{4}  + 7.5 - b (\frac{1}{3} )

The coefficients in this expression are:

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Quadratic equation brainly.com/question/1357167

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