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Fudgin [204]
3 years ago
10

A 45.0 kg ice skater stands at rest on the ice. A friend tosses the skater a 5.0 kg ball. The skater and the ball then move back

wards across the ice with a speed of 0.5 m/s. What was the speed of the ball at the moment just before the skater caught it?
Physics
1 answer:
Allushta [10]3 years ago
0 0

Answer:

u = 5 m/s

Explanation:

given,

Mass of ice skater, M = 45 Kg

initial speed = 0 m/s

mass of the ball, m = 5 Kg

velocity of skater and the ball,V = 0.5 m/s

speed of the ball = ?

using conservation of momentum

m u + M u' =( M + m ) V

initial speed of ice skater is zero

5 x u + 45 x 0 =( 45 + 5 ) V

5 u = 50 x 0.5

5 u = 25

u = 5 m/s

hence, the speed of the ball is equal to 5 m/s

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One model for a certain planet has a core of radius R and mass M surrounded by an outer shell of inner radius R, outer radius 2R
Drupady [299]

(a) 120.8 m/s^2

The gravitational acceleration at a generic distance r from the centre of the planet is

g=\frac{GM'}{r^2}

where

G is the gravitational constant

M' is the mass enclosed by the spherical surface of radius r

r is the distance from the centre

For this part of the problem,

r=R=1.17\cdot 10^6 m

so the mass enclosed is just the mass of the core:

M'=M=2.48\cdot 10^{24}kg

So the gravitational acceleration is

g=\frac{(6.67\cdot 10^{-11})(2.48\cdot 10^{24}kg)}{(1.17\cdot 10^6 m)^2}=120.8 m/s^2

(b) 67.1 m/s^2

In this part of the problem,

r=3R=3(1.17\cdot 10^6 m)=3.51\cdot 10^6 m

and the mass enclosed here is the sum of the mass of the core and the mass of the shell, so

M'=M+4M=5M=5(2.48\cdot 10^{24}kg)=1.24\cdot 10^{25}kg

so the gravitational acceleration is

g=\frac{(6.67\cdot 10^{-11})(1.24\cdot 10^{25}kg)}{(3.51\cdot 10^6 m)^2}=67.1 m/s^2

8 0
4 years ago
The angle that the Sun’s rays strike a region of Earth determines the amount of heat transferred.
Lunna [17]
This statement is true. The angle that the Sun's rays strike a region of Earth determines the amount of heat transferred. For example, as you seen on TV, a laser pointing at an object and that specific angle that the rays of the laser pointed at was being melted. Same goes for the relationship between the Sun's rays and the Earth because it has the same energy that is being emitted per second. 

3 0
4 years ago
Read 2 more answers
An object is thrown off of a cliff with a horizontal speed up 10 m/seconds. After 3 seconds the object hits the ground. Find the
Margarita [4]
Bro again the same type of sum..
well
it takes 3 second to hit the ground
the height will be
h = 5*3*3
h = 45m
horizontal distance would be
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4 0
3 years ago
Suppose a tidal basin is 6 m above the ocean at low tide and that the area of the basin is 5×107 m2. Estimate the gravitational
Neko [114]

Answer:

Potential energy will be 176.58\times 10^{11}j          

Explanation:

We have given the height of the basin is h = 6 m

Area of the basin A=5\times 10^7m^2

Volume V=area \times height=5\times 10^7\times 6=30\times 10^7m^3

Density \rho =1000kg/m^3

We know that mass is given by m=\rho V=1000\times 30\times 10^7=3\times 10^{11}kg

We know that potential energy is given by E=mgh=3\times 10^{11}\times 9.81\times 6=176.58\times 10^{11}j

3 0
3 years ago
If an object is moving at 2m/s towards a porcelain vase, do you think it will have enough momentum to brake the vase?
Alex Ar [27]

Answer: No

Explanation:

Momentum p refers to how much force is needed to change the motion of a body or object by changing its direction or braking it. In addition, momentum is directly proportional to the mass m and the velocity v:

p=mv

Now, assuming both the object and the porcelain vase have the same velocity v=2m/s but different mass, and assuming the mass of the vase is greater than the mass of the object; the momentum of the porcelain vase will be also greater than the momentum of the object.

Hence, the object will not have enough momentum to brake the vase.

8 0
3 years ago
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