Answer with Explanations:
Given:
Mass of object, m = 100 lb
height fallen, h = 600 ft
initial velocity, u = 50 ft/s
acceleration due to gravity, g = 31.5 ft/s^2
Find final velocity when it touches ground.
Solution:
Use standard kinematics equation, in the absence of air resistance and variation of g with height,
v^2 - u^2 = 2aS
where
v = final velocity
u = initial velocity
a = acceleration due to gravity
S = distance travelled
Substitute values
v^2 = u^2 + 2aS
= 50^2 + 2*31.5*600
= 40300 ft^2/s^2
Final velocity,
v = sqrt(40300) ft/s
= 200.75 ft/s
= 201 ft/s to the nearest foot.
No work at all since work can only happen if there is movement.
The gravitational force between two objects may be calculated through the equation,
F = Gm₁m₂ / d²
where G is 6.67 x 10^-11 m³/s²kg
Substituting the known values to the equation,
F = (6.67 x 10^-11 m³/s²kg)(5.0 kg)(5.0 kg) / (2.5 m)²
F = 2.668 x 10^-10 N
What you should do is reduce speed so as to be able to turn at controlled speeds, and you should also be careful when anchoring because you have to anchor from the bow rather than the stern to avoid capsizing or swamping a boat when in rough water. If you don't do this, there's a high chance that you might capsize and often that can be dangerous both for you and your wallet.
