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Fudgin [204]
2 years ago
10

A 45.0 kg ice skater stands at rest on the ice. A friend tosses the skater a 5.0 kg ball. The skater and the ball then move back

wards across the ice with a speed of 0.5 m/s. What was the speed of the ball at the moment just before the skater caught it?
Physics
1 answer:
Allushta [10]2 years ago
0 0

Answer:

u = 5 m/s

Explanation:

given,

Mass of ice skater, M = 45 Kg

initial speed = 0 m/s

mass of the ball, m = 5 Kg

velocity of skater and the ball,V = 0.5 m/s

speed of the ball = ?

using conservation of momentum

m u + M u' =( M + m ) V

initial speed of ice skater is zero

5 x u + 45 x 0 =( 45 + 5 ) V

5 u = 50 x 0.5

5 u = 25

u = 5 m/s

hence, the speed of the ball is equal to 5 m/s

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Describe how the loudness of a sound wave changes when the amplitude of the wave is increased.
tiny-mole [99]

\huge{ANSWER}

loudness is directly proportional to amplitude.

L \propto {A}^{2}

so, if amplitude is increased there will be an increase in loudness.

4 0
1 year ago
Three students are discussing the motion of an object which is described by the following equation: x(t)= -4m -(9m/s)t + (2m/s^2
Gnom [1K]

Answer:

Barret True, the speed decreases with increasing time

Explanation:

The equation they give us to describe the movement is of the form

    y = yo + v₀ t + ½ a t²

The given equation is

    y = -4 - 9 t + 2 t²

We can match term to term and find the constants

    y₀ = -4 m

    v₀ = -9 m / s

    a = 2 m / s²

With this data we can build the equation of speed and time

    v = v₀ + a t

    v = - 9 + 2 t

With this expression we see that as time increases the speed decreases since the speed and acceleration have direction is opposite

Now we can analyze the students' observations

Amadeo False, we see that the behavior is the opposite

Barret True, the speed decreases with increasing time

Chinue False With the equation we have all the data to build the speed equation as a function of time

6 0
1 year ago
If we can measure the period of a star's wobble caused by an orbiting planet, we know the _______.
Stells [14]
You would know the period of the planets orbit.
3 0
1 year ago
A 15.0-gram lead ball at 25.0°C was heated with 40.5 joules of heat. Given the specific heat of lead is 0.128 J/g∙°C, what is th
mr Goodwill [35]

Answer:

T=4985.5^{\circ}K

Explanation:

The equation that relates heat Q with the temperature change T-T_0 of a substance of mass <em>m </em>and specific heat <em>c </em>is Q=mc(T-T_0).

We want to calculate the final temperature <em>T, </em>so we have:

T=\frac{Q}{mc}+T_0

Which for our values means (in this case we do not need to convert the mass to Kg since <em>c</em> is given in g also and they cancel out, but we add 273^{\circ} to our temperature in ^{\circ}C to have it in ^{\circ}K as it must be):

T=\frac{Q}{mc}+T_0=\frac{40.5J}{(15g)(0.128J/g^{\circ}C)}+(298^{\circ}K)=4985.5^{\circ}K

3 0
1 year ago
A car moves from rest with an acceleration of 0.2ms
Lynna [10]

Explanation:

Given:

Δx = 50 m

v₀ = 0 m/s

a = 0.2 m/s²

Find: v

The problem does not involve time.  Therefore, the required equation is:

v² = v₀² + 2aΔx

Plug in values and solve:

v² = (0 m/s)² + 2 (0.2 m/s²) (50 m)

v = 4.47 m/s

6 0
1 year ago
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