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3 years ago

What are the coefficients in this expression?

Physics

2 answers:

skad [1K]3 years ago

7 0

6 and $\frac{1}{3}$

Explanation:

The expression:

6a - $\frac{3}{4} + 7.5 - \frac{b}{3}$

A coefficient is a numerical constant usually placed before a variable in an expression.

They are used to multiply variables.

Given equation is;

$6a - \frac{3}{4} + 7.5 - \frac{b}{3}$

There are two variables in this expression which are;

a and - b

$6 (a) - \frac{3}{4} + 7.5 - b (\frac{1}{3} )$

The coefficients in this expression are:

6 and $\frac{1}{3}$

learn more:

Quadratic equation brainly.com/question/1357167

#learnwithBrainly

bekas [8.4K]3 years ago

5 0

Answer:

6 and Negative one-third (D)

Explanation:

eDgE

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To solve this problem it is necessary to apply the concepts related to rate of thermal conduction

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The letter Q represents the amount of heat transferred in a time t, k is the thermal conductivity constant for the material, A is the cross sectional area of the material transferring heat, $\Delta T$ , T is the difference in temperature between one side of the material and the other, and d is the thickness of the material.

The change made between glass and air would be determined by:

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$\Delta T_{air} = (\frac{k_{glass}}{k_{air}})(\frac{L_{air}}{L_{glass}}) \Delta T_{glass}$

$\Delta T_{air} = (\frac{0.84}{0.0234})(\frac{5}{4}) \Delta T_{glass}$

$\Delta T_{air} = 44.9 \Delta T_{glass}$

There are two layers of Glass and one layer of Air so the total temperature would be given as,

$\Delta T = \Delta T_{glass} +\Delta T_{air} +\Delta T_{glass}$

$\Delta T = 2\Delta T_{glass} +\Delta T_{air}$

$20\°C = 46.9\Delta T_{glass}$

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$\Delta {Q}{t} = k_{glass}\frac{A}{L_{glass}}\Delta T_{glass}$

$\Delta {Q}{t} = 0.84*24*10 -3*0.426$

$\Delta {Q}{t} = 179W$

Therefore the correct answer is D. 180W.

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