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2 years ago

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When Emeka was first training his dog, Smooches, to heel he would give Smooches a treat when she stayed close during walks. Now

Smooches stays right by Emeka's side, even when she is not on her leash. In this case, a. the dog treats were positive reinforcers for staying close. b. the dog treats were negative reinforcers for staying close. c. the staying close was a positive reinforcer for receiving dog treats. d. the staying close was a negative reinforcer for receiving dog treats.

1 answer:

shepuryov [24]2 years ago

8 0

<span>Answer a. is correct. In this case the dog treats were positive reinforcers for staying close (the desirable behaviour). Repeated rewards for a certain behaviour work as positive reinforcers.</span>

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Suppose someone pours 0.250 kg of 20.0ºC water (about a cup) into a 0.500-kg aluminum pan with a temperature of 150ºC. Assume th

Troyanec [42]

Answer : The temperature when the water and pan reach thermal equilibrium short time later is, $59.10^oC$

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of aluminium = $0.90J/g^oC$

$c_2$ = specific heat of water = $4.184J/g^oC$

$m_1$ = mass of aluminum = 0.500 kg = 500 g

$m_2$ = mass of water = 0.250 kg = 250 g

$T_f$ = final temperature of mixture = ?

$T_1$ = initial temperature of aluminum = $150^oC$

$T_2$ = initial temperature of water = $20^oC$

Now put all the given values in the above formula, we get:

$500g\times 0.90J/g^oC\times (T_f-150)^oC=-250g\times 4.184J/g^oC\times (T_f-20)^oC$

$T_f=59.10^oC$

Therefore, the temperature when the water and pan reach thermal equilibrium short time later is, $59.10^oC$

8 0

3 years ago

What two factors are a part of thermohaline circulation

Margarita [4]

Answer:

These deep-ocean currents are driven by differences in the water's density, which is controlled by temperature (thermo) and salinity (haline). This process is known as thermohaline circulation.

Explanation:

7 0

2 years ago

Yea, gonna need some help. Thanks

natulia [17]

Answer:

t = 3.48 s

Explanation:

The time for the maximum height can be calculated by taking the derivative of height function with respect to time and making it equal to zero:

$h(t) = -16t^2+v_ot+h_o\\\\\frac{dh(t)}{dt}=0=-32t+v_o\\\\v_o = 32t$

where,

v₀ = initial speed = 110 ft/s

Therefore,

$110 = 32t\\\\t = \frac{110}{32}\\\\$

<u>t = 3.48 s</u>

8 0

2 years ago

The ball of a ballpoint pen is 0.5 mm in diameter and has an ASTM grain size of 12. How many grains are there in the ball

Fudgin [204]

Given :

The ball of a ballpoint pen is 0.5 mm in diameter and has an ASTM grain size of 12.

To Find :

How many grains are there in the ball?

Solution :

Volume of ball of the ballpoint is :

$V = \dfrac{4 \pi r^3}{3}\\\\V = \dfrac{4\times 3.14 \times 0.5^3}{3}\ mm^3\\\\V = 0.523\ mm^3$

Now, grain size of 12 has about 520000 grains/mm³.

Therefore, number of grains are :

$n = 520000\times 0.523\ grains\\\\n = 271960\ grains$

8 0

2 years ago

We divide the electromagnetic spectrum into six major categories of light, listed below. Rank these forms of light from left to

algol13

Answer:

gamma rays < X-ray < ultraviolet ray < visible light < infrared < radio wave

Explanation:

given light form,

A) radio waves,B) infrared,C) visible light,D) ultraviolet,E) X-rays,F) gamma rays

we know,

wavelength of radio wave = 10000 Km

wavelength of infrared = 700 nanometers (nm) to 1 millimeter (mm)

wavelength of visible light = 380 to 740 nm

wavelength of ultraviolet ray = 10 nm to 400 nm

wavelength of X-ray = 0.01 to 10 nm

wavelength of gamma rays = 100 picometer

so, the order of rays.

gamma rays < X-ray < ultraviolet ray < visible light < infrared < radio wave

6 0

2 years ago