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density 15.4 grams per 1.2³ cm³ ≅ 8.9 grams per cm³
<span>Find the metal that has a density of approximately 8.9 g/cm³</span>
Given :
Number of moles , n = 36.25 mol .
Molarity , M = 1.25 M .
To Find :
The volume of water required .
Solution :
Moarity is given by :
So , 
Here , n is number of moles and M is molarity .
Putting all values in above equation , we get :
Therefore , volume of water required is 29 L .
The pressure calculated as the difference between the net hydrostatic pressure and the net colloid osmotic pressure is known as: filtration pressure.
<h3>What is pressure?</h3>
Pressure can be defined as a measure of the force exerted per unit area of an object or body. Thus, it is usually measured in Newton per meter square.
<h3>The types of pressure.</h3>
In Science, there are different types of pressure and these include the following:
Filtration pressure is a pressure that is typically calculated as the difference between the net hydrostatic pressure and the net colloid osmotic pressure. Also, it promotes the filtration of fluid through a membrane.
Read more on pressure here: brainly.com/question/24827501
Molar mass O2 = 31.99 g/mol
Molar mass CO2 = 44.01 g/mol
Moles ratio:
<span>C3H8 + 5 O2 = 3 CO2 + 4 H2O
</span>
5 x 44.01 g O2 ---------------- 3 x 44.01 g CO2
( mass of O2) ------------------ 37.15 g CO2
mass of O2 = 37.15 x 5 x 44.01/ 3 x 44.01
mass of O2 = 8174.8575 / 132.03
mass of O2 = 61.916 g
Therefore:
1 mole O2 ----------------- 31.99 g
moles O2 -------------------- 61.916
moles O2 = 61.916 x 1 / 31.99
moles = 61.916 / 31.99 => 1.935 moles of O2
