All categories

3 years ago

Why does hydrogen peroxide turn your skin white

Chemistry

2 answers:

Julli [10]3 years ago

4 0

Answer:

Hydrogen Peroxide is known as a dental “debriding agent”. But when used on skin for minor wounds it will foam and turn surrounding tissue white. ... H2O2 decomposes easily to make water (H2O) and a single free oxygen atom which is looking for something to react with - like your skin.

Explanation:

Andreas93 [3]3 years ago

3 0

Known As Debriding Agent

You might be interested in

Cuando los volcanes entran en erupción lanzan al exterior porciones de materia muy variada ¿cuales fueron los productos de la er

DENIUS [597]

Answer:

The Etna volcano when it previously erupted released a lot of smoke, and then volcanic lava.

Explanation:

The eruption of this volcano was on the Italian island of Sicily.

Where there were large columns of smoke and after that the volcanic magma in a viscoelastic state was released into the external environment.

Some sources claim that the eruption of this volcano reached the areas of Zaffanera.

7 0

3 years ago

what is the approximate ph at the equivalence point of a weak acid-strong base titration if 25 ml of aqueous formic acid require

vivado [14]

Answer:

pH at equivalence point is 8.52

Explanation:

$HCOOH+NaOH\rightarrow HCOO^{-}Na^{+}+H_{2}O$

1 mol of HCOOH reacts with 1 mol of NaOH to produce 1 mol of $HCOO^{-}$

So, moles of NaOH used to reach equivalence point equal to number of moles $HCOO^{-}$ produced at equivalence point.

As density of water is 1g/mL, therefore molarity is equal to molality of an aqueous solution.

So, moles of $HCOO^{-}$ produced = $\frac{29.80\times 0.3567}{1000}moles=0.01063moles$

Total volume of solution at equivalence point = (25+29.80) mL = 54.80 mL

So, at equivalence point concentration of $HCOO^{-}$ = $\frac{0.01063\times 1000}{54.80}M=0.1940M$

At equivalence point, pH depends upon hydrolysis of $HCOO^{-}$ . So, we have to construct an ICE table.

$HCOO^{-}+H_{2}O\rightleftharpoons HCOOH+OH^{-}$

I: 0.1940 0 0

C: -x +x +x

E: 0.1940-x x x

So, $\frac{[HCOOH][OH^{-}]}{[HCOO^{-}]}=K_{b}(HCOO^{-})=\frac{10^{-14}}{Ka(HCOOH)}$

species inside third bracket represent equilibrium concentrations

So, $\frac{x^{2}}{0.1940-x}=5.56\times 10^{-11}$

or, $x^{2}+(5.56\times 10^{-11}\times x)-(1.079\times 10^{-11})=0$

So, $x=\frac{-(5.56\times 10^{-11})+\sqrt{(5.56\times 10^{-11})^{2}+(4\times 1.079\times 10^{-11})}}{2}$

So, $x=3.285\times 10^{-6}M$

So, $pH=14-pOH=14+log[OH^{-}]=14+logx=14+log(3.285\times 10^{-6})=8.52$

5 0

3 years ago

What color would you expect a weak base to turn the paper?

Darina [25.2K]

Answer:

Blue litmus paper paper turns red under acidic conditions. Red litmus paper turns blue under basic or alkaline conditions. If you're using a universal indicator, the weak base should turn those blue.

Explanation:

7 0

4 years ago

b. Sugar and salt are both white, crystalline powders that dissolve in water. If you were given an unknown sample that contained

NikAS [45]

Answer:

Explanation:

Sugar and Salt even thought they both dissolve in water they both dissolve in different ways. When salt dissolves in water, its individual types of ions are torn apart from each other, while Sugar molecules stay together when dissolved in water, and therefore the molecules remain the same when dissolved in water. This being said in science using your senses can be just as valuable as using calculations. In this case both Sugar and Salt taste differently. Sugar is sweet while Salt is salty. Therefore tasting the substance can be the easiest and most accurate way of determining the substance.

Read more at Answer.Ya.Guru – https://answer.ya.guru/questions/4803546-sugar-and-salt-are-both-white-crystalline-powders-that-dissolve.html

5 0

2 years ago

Name the following alkane:

vladimir1956 [14]

The names of the alkanes are 2,2- dimethylbutane, 2,4- dimethylhexane, 2,2,3,3- tetramethylbutane and 4- ethyl, 3,6- dimethyl heptane.

Alkanes are saturated hydrocarbon in the organic chemistry. These are organic compounds that consists of single bonded carbon and hydrogen atoms. The common formula for writing an alkane is given by CₙH₂ₙ₊₂.

Alkanes are further divided into three more types which are:

1. Chain alkanes

2. Cycloalkanes

3. Branched alkanes

Hydrogenation method is used for preparation of alkanes from alkene and alkyne.

The names of the given compounds are:

Part A:

2,2- dimethyl butane

Part B:

2,4- dimethyl hexane

Part C:

2,2,3,3- tetramethyl butane

Part D:

4- ethyl, 3,6- dimethyl heptane

Learn more about alkanes from the link given below.

brainly.com/question/16837399

#SPJ1

4 0

1 year ago