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Ronch [10]
3 years ago
14

para una practica de laboratorio se requiere una disolucion de acido nitrico HNO3 al 3,5M,pero se dispone de un frasco de 1 litr

o cuya concentrasion es de 8M, cual es el volumen final que se obtendra al diluir todo el contenido​
Chemistry
1 answer:
aliya0001 [1]3 years ago
5 0

Answer:

hindi ko alam yan

PANO BA YAN

Explanation:

EWAN

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The fermentation of C6H12O6 will produce carbon dioxide and
Leokris [45]

Answer:

ethanol

Explanation:

CO2 is carbon dioxide

C2H5OH is ethanol and we know that because that is what is left after taking out the CO2

5 0
3 years ago
An internal combustion engine relies primarily on the efficient production of energy by the combination of oxygen (02) and gasol
jeka57 [31]
Answer is: <span>the exact ratio of oxygen to octane for is 12.5 : 1.
</span>Balanced chemical reaction: C₈H₁₈ + 25/2O₂ → 8CO₂ + 9H₂O or multiply by 2:
2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O.
There same number of atoms on both side of balanced chemical reaction: eight carbon atoms, eighteen hydrogen atoms and twenty five oxygen atoms.

7 0
3 years ago
With what compound will nh3 experience only dispersion intermolecular forces? with what compound will nh3 experience only disper
Burka [1]
Answer is: ammonia experience only dispersion intermolecular forces with BF₃ (boron trifluoride) because BF₃ is only nonpolar molecule (vectors of dipole moments cansel each other, dipole moment is zero).
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6 0
3 years ago
Read 2 more answers
Consider the followong balanced reaction. What mads in g of co2 can be formed from 288 mg of o2. Assume that there is excess c3h
Gwar [14]

<u>Answer:</u>

<em>0.264 g of CO_2 can be formed from 288 mg of O_2</em>

<u>Explanation:</u>

The balanced chemical equation is

2 C_3 H_7 OH+9 O_2> 6 CO_2+8 H_2 O

The conversions are  

Mass in mg O_2 is converted to mass in g O_2  

Mass in g O_2 is converted to moles O_2 by dividing with molar mass  

Moles O_2 is converted to moles CO_2  by using the mole ratio of O_2:CO_2 is 9 : 6

Moles CO_2  is converted to mass CO_2 by multiplying with molar mass CO_2

mass in mg O_2  > mass in g O_2 >moles O_2 > moles CO_2 > mass CO_2

288mg O_2 \times \frac{(1g O_2)}{(1000mg O_2 )} \times \frac {(1molO_2)}{(32gO_2 )}\times\frac {(6mol CO_2)}{(9mol O_2 )} \times \frac {(44.0 gCO_2)}{(1mol CO_2 )}

=0.264g (Answer)

7 0
4 years ago
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3 years ago
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