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Ronch [10]
3 years ago
14

para una practica de laboratorio se requiere una disolucion de acido nitrico HNO3 al 3,5M,pero se dispone de un frasco de 1 litr

o cuya concentrasion es de 8M, cual es el volumen final que se obtendra al diluir todo el contenido​
Chemistry
1 answer:
aliya0001 [1]3 years ago
5 0

Answer:

hindi ko alam yan

PANO BA YAN

Explanation:

EWAN

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Why do thermistors increase in conductivity when heated? What happens in normal metals? Explain on the atomic level.
Marysya12 [62]

Metal conductivity generally goes down or resistivity goes up with temperature goes up.

7 0
2 years ago
D) does not dissociate in solution.
natima [27]

Answer:

According to the proton theory of acids and bases by J. Brønsted and T. Lowry, the  acid is<u> proton donor</u>.

Explanation:

According to the Bronsted lowry concept an acid is substance that gives protons or hydrogen ion while,

Base is substance that accept hydrogen ion or proton.

Consider the following example:

NH₃ + HCl  →  NH₄⁺ + Cl⁻

In this example HCl is Bronsted lowry acid it gives H⁺ while ammonia is Bronsted lowry base because it accept H⁺.

This also gives the concept of conjugate acid and base. In given example Cl⁻ is conjugate base of HCl while NH₄⁺ is conjugate acid of ammonia.

4 0
3 years ago
What is the total pressure of a gas mixture containing partial pressures of
Advocard [28]

Answer:

1.54 atm

Explanation:

By Dalton's Law Of partial pressure,

Total Pressure = Sum of all partial pressures

So,P= P1 + P2 + P3

Therefore, P=0.23+0.42+0.89

=1.54 atm

8 0
2 years ago
Show
SIZIF [17.4K]

Answer: 0.9375 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}     .....(1)

Molarity of HCl solution = 0.75 M

Volume of HCl solution = 25.0 mL = 0.025 L

Putting values in equation 1, we get:

\text{Moles of} HCl={0.75}\times{0.025}=0.01875moles  

CaCO_3(s)+2HCl(aq)\rightarrow CaCl_2(s)+CO_2(g)+H_2O(l)  

According to stoichiometry :

2 moles of HCl require = 1 mole of CaCO_3

Thus 0.01875 moles of HCl will require=\frac{1}{2}\times 0.01875=0.009375moles  of CaCO_3

Mass of CaCO_3=moles\times {\text {Molar mass}}=0.009375moles\times 100g/mol=0.9375g

Thus 0.9375 g of CaCO_3 is required to react with 25.0 ml of 0.75 M HCl

6 0
3 years ago
Which came first the henry g.j moseley atomic model or the niels bohr atomic model?
Gnesinka [82]
The niels bohr model
5 0
3 years ago
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