Question

A particular satellite with a mass of m is put into orbit around Ganymede (the largest moon of Jupiter) at a distance 300 km from the surface. What is the gravitational force of attraction between the satellite and the moon? (Ganymede has a mass of 1.48x1023 kg and a radius of 2631 km.) ​mass of satellite =5×10^8 kg.​

Answer 1

Answer:

F = 402.18 N

Explanation:

Given that,

A particular satellite with a mass of m is put into orbit around Ganymede (the largest moon of Jupiter) at a distance 300 km from the surface. Let the mass of the satellite is 350 kg.

We need to find the gravitational force of attraction between the satellite and the moon.

The formula for the gravitational force is given by :

$F=G\dfrac{Mm}{(R+h)^2}$

M is mass of Ganymede

m is mass of satellite

R is Radius of Ganymede

h is distance = 300 km

Putting all the values,

$F=6.67\times 10^{-11}\times \dfrac{1.48\times 10^{23}\times 350}{(2631\times 10^{3}+300\times 10^3)^2}\\F=402.18\ N$

So, the required force of attraction between the satellite and the moon is 402.18 N.