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alina1380 [7]
3 years ago
9

What should i write on a essay about glue and liquid corn starch

Chemistry
1 answer:
PolarNik [594]3 years ago
8 0
Hmm... interesting topic you're writing about here!
Well, for this essay, there must be specific criteria, correct? I'll make some suggestions, but of course you don't have to go by them if you don't like 'em. So... here they are!:

- List the physical and chemical properties of glue
- List the physical and chemical properties of liquid corn starch
- Compare and contrast the physical and chemical properties of glue with the physical and chemical properties of liquid corn starch
- You can conduct some experiments with the two substances also! You can mix the two together and see how they react with each other, and incorporate the results of the experiment into your essay.
- You can mix glue with some other liquid substances too, and incorporate your results into your essay. You can see whether each substance the glue mixes with creates a homogeneous or heterogeneous mixture, etc.
- You can mix liquid corn starch with some other liquid substances too, and incorporate your results into your essay. You can see whether each substance the liquid corn starch mixes with creates a homogeneous or heterogeneous mixture, etc.

That's all I can come up with at the moment. Maybe you'll take some of these suggestions into consideration...? Anyhow, I hope I helped somehow! :)
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Read 2 more answers
Calculate the energy required to heat 322.0g of ethanol from −2.2°C to 19.6°C . Assume the specific heat capacity of ethanol und
just olya [345]

Answer:

There is 17.1 kJ energy required

Explanation:

Step 1: Data given

Mass of ethanol = 322.0 grams

Initial temperature = -2.2 °C = 273.15 -2.2 = 270.95K

Final temperature = 19.6 °C = 273.15 + 19.6 = 292.75 K

Specific heat capacity = 2.44 J/g*K

Step 2: Calculate energy

Q = m*c*ΔT

⇒ m = the mass of ethanol= 322 grams

⇒ c = the specific heat capacity of ethanol = 2.44 J/g*K

⇒ ΔT = T2 - T1 = 292.75 - 270.95 = 21.8 K

Q = 322 * 2.44 * 21.8 = 17127.8 J = 17.1 kJ

There is 17.1 kJ energy required

3 0
3 years ago
Air containing 20.0 mol% water vapor at an initial pressure of 1 atm absolute is cooled in a 1- liter sealed vessel from 200°C t
chubhunter [2.5K]

Answer:

This solution is quite lengthy

Total system = nRT

n was solved to be 0.02575

nH20 = 0.2x0.02575

= 0.00515

Nair = 0.0206

PH20 = 0.19999

Pair = 1-0.19999

= 0.80001

At 15⁰c

Pair = 0.4786atm

I used antoine's equation to get pressure

The pressure = 0.50

2. Moles of water vapor = 0.0007084

Moles of condensed water = 0.0044416

Grams of condensed water = 0.07994

Please refer to attachment. All solution is in there.

6 0
3 years ago
Is the following a physical or chemical change?
tester [92]

Answer:

chemical change

Explanation:

electrolysis process by which electric current is passed through a substance to effect a chemical change.

6 0
3 years ago
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