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sdas [7]
4 years ago
13

HELP MEHHHHH were does the first stage of cellular respiration occur ?

Chemistry
1 answer:
Reptile [31]4 years ago
7 0

Answer:

mitochondria

Explanation:

Cellular respiration occurs primarily in the mitochondria of your cells. The mitochondria is like the powerhouse of cells .

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Identify whether each compound is a straight chain, branched chain, or cycloalkane,
Delvig [45]

Answer:

First Part: branched chain, cycloalkane, straight chain

Second Part: straight chain, branched chain, cycloalkane.

Explanation:

Edg 2021

7 0
3 years ago
A multi-nutrient fertilizer contains several different nitrogen containing compounds. The fertilizer is 54.8% CH4N2O (urea), 26.
vesna_86 [32]

Answer:

  • <u><em>9.01 g of fertilizer</em></u>

Explanation:

Assume initially that the amount in grams of the multinutrient fertilizer is 100 g, and calculate the amount of nitrogen supplied by every compound present in these 100 g of fertilizer.

<u>1) Urea (CH₄N₂O)</u>:

  • Molar mass of urea: 60.06 g/mol
  • Atomic mass of N: 14.007 g/mol
  • Total mass of N in the formula: 2 × 14.007 g/mol = 28.014 g/mol
  • Amount of N in 100 g of compound: 100 g × 54.8% × 28.014 g / 60.06 g =  25.56 g

<u>2) KNO₃</u>

  • Molar mass of KNO₃: 101.1032 g/mol
  • Atomic mass of N: 14.007 g/ mol
  • Total mass of N in the formula: 14.007 g/mol
  • Amount of N in 100 of the compound: 100 g × 26.3% × 14.007 / 101.1032 = 3.64 g

<u>3) (NH₄)₂PO₄</u>

  • Molar mass of (NH₄)₂PO₄: 132.06 g/mol
  • Atomic mass of N: 14.007 g/ mol
  • Total mass of N in the formula: 2×14.007 g/mol = 28.014 g/mol
  • Amount of N in 100 of the compound: 100 g × 14.1% × 14.007 / 132.06 = 2.99 g

4) <u>Total mass of N in 100 g of fertilizer</u>:

Add all the amounts of N obtained above

  • 25.56g + 3.69 g + 2.99 g = 32.19 g of N

5) <u>Mass of fertilizer that should be applied to provide 2.90 g of N to a plant</u>.

Set a proportion:

  • 32.19 g of N / 100 g of fertilizer = 2.90 g of N / X

Solve for X:

  • X = 2.90 g of N × 100 g of fertilizer / 32.19 g of N = 9.01 g of fertilizer

That is the answer: 9.01 g of fertilizer should be applied to provide 2.90g  of N to a plant.

4 0
3 years ago
Advantages and disadvantages of extracting petroleum products from oil sands
Brut [27]
<span> Advantages
- large resource of potential oil
- biggest resource is in Canada, whereas the largest reserves of crude oil are in Saudi Arabia and Venezuela
</span><span><span>- It requires less processing than oil shale and presents fewer problems than oil shale
- Processing is mainly by hot water.</span>- Exploitation has only started recently so low cost reserves are still available.



Disadvantages
- Most of the resource is uneconomic at present oil prices - so exploitable reserves are less than for crude oil
- Oil sands require mining, which is more complex and costly than drilling and pumping crude oil.
- Processing requires more energy than for crude oil.
- Resources are less than for oil shale - which is available in very large reserves in the US and Australia.</span>
<span>- Refining is more difficult because the product is in the form of bitumen - requiring cracking to produce a saleable product.
- because of the increased processing and refining, more carbon is released per unit of useable energy than for crude oil</span>

6 0
3 years ago
Help me write why it’s B
ollegr [7]
There are other cells besides single cells that are ussally found in multicellular organisms than singular
4 0
3 years ago
How many protons are in sodium.
Reika [66]

11 protons

Hope this helps :)

5 0
3 years ago
Read 2 more answers
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