Answer:
3.213J/mol
Explanation:
first specific heat capacity of water = 4200J/Kg K
Q=mass×temperature difference×specific heat capacity
Q=1.53×(24.3-20)×4200
Q=25.704 J
heat of solution= quantity of heat ÷ amount of substance
heat of solution= 25.704÷8
heat of solution= 3.213J/mol
Answer:
The heat absorbed by water is 39243.75 J.
Explanation:
Given data:
Mass of water = 375.0 g
Heat absorbed by water= ?
Initial temperature = 10.0°C
Final temperature = 35.0 °C
The specific heat capacity of water = 4.186 j/g.°C
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 35°C - 10°C
ΔT = 25°C
Q = m.c. ΔT
Q = 375.0 g× 4.186 j/g °C × 25°C
Q = 39243.75 J
The heat absorbed by water is 39243.75 J.
Answer:
1) 4Fe + 3O2 → 2Fe2O3
2) H2 + Cl2 → 2HCl
3) 2Ag + H2S → Ag2S + H2
4) CH4 + 2O2 → CO2 + 2H2O
5) 2HgO → 2Hg + O2
6) 2Co + 3H2O → Co2O3 + 3H2
Answer:
0.249087
Explanation:
1.5 x 10^23 atoms x 1 mole / 6. 022 x 10^23 atoms
= 0.249087
An example is when light goes from traveling on air to the water. A famous experiment that is done on many schools to prove this is the one with the pencil on a cup of water. I added both pictures so you are able to visualise what I'm trying to say. The pencil "bends" on the water because of a phenomenon called refraction. <span>When light enters water, it cannot move as fast as it </span>does in air, therefore, a<span>s the light enters the water, it </span>bends<span> away from its original path. Hope I was able to help!!</span>
