Ask question

Ask question

All categories

3 years ago

14

What is the maximum amount of silver (in grams that can be plated out of 4.7 l of an agno3 solution containing 3.2 % ag by mass?

assume that the density of the solution is 1.01 g/ml?

1 answer:

Alex3 years ago

5 0

The maximum amount of silver will be all of that contained in the solution.
Silver in solution:
Solution volume = 4,700 ml
Solution mass = 1.01 x 4,700
Solution mass = 5170 g

Amount of silver = 5,170 x 0.032
Amount of silver = 165.44 grams

You might be interested in

if 30L of oxygen is cooled from 200 degrees C to 1 degree C at constant pressure, what is the new volume of the oxygen?

gayaneshka [121]

The new volume of the oxygen would be 17.4 L. I think it's 17.4 L but I don't know. I hope it was helpful.

8 0

3 years ago

What is all of the living organisms on earth and the places they live in?

romanna [79]

Answer:

Biosphere

Explanation:

The biosphere is the area of Earth where living things exist. The biosphere is divided into regions known as biomes. In general, biomes are areas with a particular type of climate and similar plant and animal species.

8 0

3 years ago

FOR LondonCreamCakes<br> no sure if its right but im trying to help.. lol dont mind all the tabs

MAVERICK [17]

Answer:

It kinda helps but not really

Thanks for trying anyway doe!

Explanation:

7 0

3 years ago

Air at 7S°F and14.6 though a cfm(cubic ft per minute) and the The flow rate is 48000 psia flows though a rectangular duct of Ix2

IgorLugansk [536]

Explanation:

The given data is as follows.

Air is at $75^{o}F$ and 14.6 psia.

$\varepsilon$ = 0.00015 ft, Flow rate, (Q) = 48000 $ft^{3}/m$

(a) Formula to calculate hydraulic radius $(r_{H})$ is as follows.

$r_{H} = \frac{\text{free flow area}}{\text{wet perimeter}}$

= $\frac{2 \times 1}{2(1) + 2(2)}$

= $\frac{1}{3}$ ft

Formula for equivalent diameter is as follows.

$D_{eq} = 4 \times r_{H}$

= $4 \times \frac{1}{3} ft$

= $\frac{4}{3}$ ft

(b) Formula for velocity floe is as follows.

Q = VA

V = $\frac{Q}{A}$

= $\frac{48000}{2 \times 1}$ ft/min

= 24000 ft/min

(c) Formula to calculate Reynold's number is as follows.

$R_{e}$ = $\frac{D \times V \times \rho}{\mu}$

= $\frac{\frac{4}{3} \times 24000 \times 0.0744}{0.0443}$ (as $\rho = 0.0744 lb/ft^{3}$ and $\mu$ = 0.0443 lb/ft. hr)

= 53742.66 hr/min

As 1 hr = 10 min. So, $53742.66 hr/min \times \frac{60 min}{1 hr}$

= 3224559.6

(d) Formula to calculate pressure drop $(\Delta P)$ is as follows.

$\frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}$

Putting the given values into the above formula as follows.

$\frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}$

= $\frac{4 \times 0.00015 \times 100 \times 0.0744 \times (24000)^{2}}{2 \times \frac{4}{3} \times {4}{3}}$

= 6.238 $lb/ft^{2}$

5 0

3 years ago

Can you look at the picture Look at the picture ASAP and help please?

Murrr4er [49]

Answer:

Volume of the reaction vessel is increased - shift to the left

The reaction is cooled down - shift to the right

H2 is added to the system - shift to the right

The pressure of the system is decreased - shift to the left

A catalyst is added to the system - no change

Water is removed from the system - shift to the right

Explanation:

When a constraint such as a change in temperature, pressure or volume is imposed on a reaction system in equilibrium, the equilibrium position will shift in such a way as to annul the constraint.

When the volume of a reaction system is increased, the equilibrium position shifts in the direction in which there is the highest total volume. This is the left hand side.

Since the reaction is exothermic (heat is given out) when the reaction is cooled down, the forward reaction is favoured.

Adding of reactants shifts the equilibrium position to the right hand side hence when H2 is added, the equilibrium position shifts to the right.

Decreasing the pressure shifts the equilibrium position to the direction of higher total volume hence the equilibrium shifts to the left when pressure is decreased.

A catalyst has no effect on the equilibrium position. It increases the rate of forward and reverse reaction to the same extent hence the equilibrium position is unaffected.

Removal of water from the system increases the rate of forward reaction since a product is being removed from the reaction system.

7 0

3 years ago