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Sedbober [7]
3 years ago
12

1. An 800-gram bowling ball is rolling in a straight line toward you. If its momentum is 16 kg•m/sec, how fast is it traveling?

Physics
1 answer:
ziro4ka [17]3 years ago
3 0

<u>Answer:</u>

The ball is rolling at a speed of 0.02 meter per second.

<u>Step by step explanation:</u>

We are given that there is a 800 gram bowling ball rolling in a straight line. If its momentum is given to be 16 kg.m/sec, we are to find its velocity.

For this, we will use the formula of momentum.

<em>Momentum = mass × velocity</em>

16 = 800 × velocity

Velocity = 16/800 = 0.02 meter per second

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Answer:

B. Water and sugar.

Explanation:

In the given options water and sugar would be the poor conductor of electricity. Other given options such as water and salt, water and Hcl and water and NaOH are better conductor of electricity because Hcl ,NaOH, salt (Nacl) can break into their ionic form whereas water and sugar will not.

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On February 15, 2013, Asteroid 2012 DA14 passed within 17,200 miles [mi] of the surface of the Earth at a relative speed of 7.8
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Answer:

The total amount of energy that would have been released if the asteroid hit earth = The kinetic energy of the asteroid = 1.29 × 10¹⁵ J = 1.29 PetaJoules = 1.29 PJ

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Explanation:

Kinetic energy = mv²/2

velocity of the asteroid is given as 7.8 km/s = 7800 m/s

To obtain the mass, we get it from the specific gravity and diameter information given.

Density = specific gravity × 1000 = 3 × 1000 = 3000 kg/m³

But density = mass/volume

So, mass = density × volume.

Taking the informed assumption that the asteroid is a sphere,

Volume = 4πr³/3

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Mass of the asteroid = density × volume = 3000 × 14137.2 = 42411501 kg = 4.24 × 10⁷ kg

Kinetic energy of the asteroid = mv²/2 = (4.24 × 10⁷)(7800²)/2 = 1.29 × 10¹⁵ J

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