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3 years ago

1. An 800-gram bowling ball is rolling in a straight line toward you. If its momentum is 16 kg•m/sec, how fast is it traveling?

Physics

1 answer:

ziro4ka [17]3 years ago

3 0

<u>Answer:</u>

The ball is rolling at a speed of 0.02 meter per second.

<u>Step by step explanation:</u>

We are given that there is a 800 gram bowling ball rolling in a straight line. If its momentum is given to be 16 kg.m/sec, we are to find its velocity.

For this, we will use the formula of momentum.

<em>Momentum = mass × velocity</em>

16 = 800 × velocity

Velocity = 16/800 = 0.02 meter per second

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aivan3 [116]

<h2>Answer:</h2>

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alexandr402 [8]

Answer:

d = 1.30 mm

Explanation:

given,

wavelength of the light source (λ)= 502 nm

slits is separated (d) = ?

distance to form interference pattern(D) = 1.35 m

20 th fringe

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now,separation between to slits

$d = \dfrac{m\lambda\ D}{y}$

where y is the fringe width

$d = \dfrac{20 \times 502\times 10^{-9}\ \times 1.35}{0.0104}$

$d = \dfrac{13354\times 10^{-9}}{0.0104}$

d = 1.30 mm

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$Q_1 = Q_2$