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3 years ago

you buy a calculator for $65. A 6% sales tax is added. Write and solve an equation to find the total price,t.

Mathematics

2 answers:

laila [671]3 years ago

8 0

Answer:

The total price of the calculator is $68,90.

Step-by-step explanation:

If we look at the information we have, we can establish that the initial cost of the calculator is $ 65, and that at the time of payment 6% of taxes were added.

Now we must determine what the total value to be paid for the calculator will be.

The correct form would be applying 6% to 65, which will give us the value of the tax:

t = 65 . 0,06 

t = 3,90 

Knowing that $ 3.90 is the value of the tax, we should only add it to the initial value of the calculator:

$ 65 + $ 3.90 = $ 68.90

Therefore, the calculator will cost $ 68.90.

STALIN [3.7K]3 years ago

3 0

Answer:

t = 65 + 65(.06)

t = $68.90

Step-by-step explanation:

A 6% sales tax means you have to multiply the price of the calculator by 0.06.

So the tax would be

tax = 65(.06)

tax = $3.90

the total price would be $65 plus the tax ($3.90)

the total price is $68.90.

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The temperature of a certain solution is estimated by taking a large number of independent measurements and averaging them. The

Mademuasel [1]

Answer:

(a) The 95% confidence interval for the temperature is (36.80°C, 37.20°C).

(b) The confidence level is 68%.

(d) The 95% confidence interval for the temperature if 10 measurements were made is (36.93°C, 37.07°C).

Step-by-step explanation:

Let X = temperature of a certain solution.

The estimated mean temperature is, $\bar x=37^{o}C$ .

The estimated standard deviation is, $s=0.1^{o}C$ .

(a)

The general form of a (1 - α)% confidence interval is:

$CI=SS\pm CV\times SD$

Here,

SS = sample statistic

CV = critical value

SD = standard deviation

It is provided that a large number of independent measurements are taken to estimate the mean and standard deviation.

Since the sample size is large use a z-confidence interval.

The critical value of z for 95% confidence interval is:

$z_{0.025}=1.96$

Compute the confidence interval as follows:

$CI=SS\pm CV\times SD\\=37\pm 1.96\times 0.1\\=37\pm0.196\\=(36.804, 37.196)\\\approx (36.80^{o}C, 37.20^{o}C)$

Thus, the 95% confidence interval for the temperature is (36.80°C, 37.20°C).

(b)

The confidence interval is, 37 ± 0.1°C.

Comparing the confidence interval with the general form:

$37\pm 0.1=SS\pm CV\times SD$

The critical value is,

CV = 1

Compute the value of P (-1 < Z < 1) as follows:

$P(-1$

The percentage of z-distribution between -1 and 1 is, 68%.

Thus, the confidence level is 68%.

(c)

The confidence interval for population mean can be constructed using either the z-interval or t-interval.

If the sample selected is small and the standard deviation is estimated from the sample, then a t-interval will be used to construct the confidence interval.

But this will be possible only if we assume that the population from which the sample is selected is Normally distributed.

Thus, the necessary assumption is that the population is normally distributed.

(d)

For n = 10 compute a 95% confidence interval for the temperature as follows:

The (1 - α)% t-confidence interval is:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}$