Answer:
200 grams is the mass of 15% of the solution of lime that is formed by dissolving 30g of calcium hydroxide in water.
Explanation:
Mass of solution = M
Mass percentage of the solution of lime = 15%
Mass of lime or calcium hydroxide = m = 30 g
The Formula of mass percentage is given as :
On substituting the values in ab above formula :
200 grams is the mass of 15% of the solution of lime that is formed by dissolving 30g of calcium hydroxide in water.
Hello!
Data:
Molar Mass of H2CO3 (carbonic acid)
H = 2*1 = 2 amu
C = 1*12 = 12 amu
O = 3*16 = 48 amu
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Molar Mass of H2CO3 = 2 + 12 + 48 = 62 g/mol
Now, since the Molarity and ionization constant has been supplied, we will find the degree of ionization, let us see:
M (molarity) = 0.01 M (Mol/L) →
Use: Ka (ionization constant) =
Now, we will calculate the amount of Hydronium [H3O+] in carbonic acid (H2CO3), multiply the acid molarity by the degree of ionization, we will have:
And finally, we will use the data found and put in the logarithmic equation of the PH, thus:
Data:
apply the data to formula
Note:. The pH <7, then we have an acidic solution (weak acid).
Now, let's find pOH by the following formula:
I Hope this helps, greetings ... DexteR! =)