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sladkih [1.3K]
3 years ago
6

Water contained in a reservoir is controlled by a dam. The energy of the trapped water is

Chemistry
1 answer:
Lana71 [14]3 years ago
6 0
Another example of potential energy.
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A 50 L cylinder is filled with argon gas to a pressure of 10130.0 kPa at 300°C. How many moles of argon gas does the cylinder co
Vlad1618 [11]
To answer this question, we will use the general gas law which states that:
PV = nRT where:
P is the pressure of the gas = <span>10130.0 kPa
</span>V is the volume of the gas = 50 liters
n is the number of moles that we want to calculate
R is the gas constant = <span>8.314 L∙kPa/K∙mol
T is the temperature = 300+273 = 573 degree kelvin

Substitute with the givens in the equation to get the number of moles as follows:
</span><span>10130 * 50 = n * 8.314 * 573
506500 = 4763.922 n
n = </span>506500 / 4763.922
n = 106.3199 moles
7 0
3 years ago
Balance the chemical equation. Based on the equation, how many grams of chlorine are produced when the sodium chloride decompose
aliina [53]

Answer:

Answer is in the photo

Explanation:

Have a nice day and if the photo isn’t visible let me know! :)

5 0
3 years ago
Read 2 more answers
A Weather man reports
notsponge [240]

Answer:

???

Explanation:

3 0
3 years ago
Identify the products and the reactants in the following chemical equations
liq [111]

Answer:

1-Mg+O2=reactants                  MgO-product

2-CaNr2+AlCl3=reactants        CaCI2+AIBr3=product

3-C2H4+O2=reactants              H2O+CO2=product

Explanation:

Reactants are on the left side and products on the right.

6 0
2 years ago
Certain compound contains 7.3% carbon, 4.5% hydrogen, 36.4% oxygen, and 31.8% nitrogen. It’s reality molecular mass is 176.0. Fi
erastovalidia [21]

Answer:

The answer to your question is:

Explanation:

Data

carbon        7.3%          =     7.3g

hydrogen    4.5%         =      4.5g

oxygen       36.4%         =     36.4 g

nitrogen     31.8%         =     31.8 g

Now

For carbon

                    12 g --------------------1 mol

                    7.3 g     -------------     x

                       x = 7.3/12 = 0.608 mol

For hydrogen

                 1 g   --------------------  1 mol

                 4.5 g  ------------------    x

                   x = 4.5 mol

For oxygen

             16 g ------------------- 1 mol

             36.4 g ----------------    x

             x = 2.28 mol

For nitrogen

              14 g   ----------------   1 mol

              31.8 g ---------------    x

             x = 2.27 mol

Now divide by the lowest result, the is 0.608 from carbon

carbon              0.608/0.608 = 1

hydrogen           4.5/ 0.608 = 7.4

oxygen              2.28/0.608 = 3.75

nitrogen             2.27/0.608 = 3.73

Empirical formula = CH₇O₄N₄

     

6 0
3 years ago
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