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Degger [83]
2 years ago
7

calculate the pressure exerted by a mercury column of 76 cm high at its bottom.Given that density of mercury is 13600kg/m^3 and

g=9.8​

Physics
1 answer:
Amanda [17]2 years ago
5 0

Answer:

Explanation:I don't say you have to mark my ans as brainliest but if you think it has really helped you plz don't forget to thank me ...

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A baseball pitcher throws a ball at 40 ms^-1. if the acceleration is approximately constant over a distance of 2 m, how large is
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We have the equation of motion v^2=u^2+2as, where v i the final velocity, u is the initial velocity, a is the acceleration and s is the displacement

Here final velocity, v = 40m/s

        Initial velocity, u = 0 m/s

        Displacement s = 2 m

Substituting 40^2=0^2+2*a*2\\ \\ a=400m/s^2

So the baseball pitcher accelerates at 400m/s^2 to release a ball at 40 m/s.

4 0
2 years ago
a race car driver achieved a speed of 53m/s in 14 seconds after taking off from rest from the starting line. what was the averag
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Answer:

53/14

Explanation:

average acceleration = (Vfinal -Vintial)/ time taken

3 0
2 years ago
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If a beam of light enters one medium from another medium, what quantity does not change?
wlad13 [49]

The answer is D- Frequency

4 0
3 years ago
A conducting rod moves perpendicularly through a uniform magnetic field. How does the emf change if the magnetic field is increa
Marysya12 [62]

Answer:

c) It increases by a factor of 8

Explanation:

According to Faraday's law (and Lenz' law), the induced EMF is given as the rate of change of magnetic flux.

Mathematically:

V = -dФ/dt

Magnetic flux, Ф, is given as:

Ф = BA

where B  = magnetic field strength and A = Area of object

Hence, induced EMF becomes:

V = -d(BA)/dt  or -BA/t

If the magnetic field is increased by a factor of 4, (B_n = 4B) and the time required for the rod to move is decreased by a factor of 2 (t_n = t/2), the induced EMF becomes:

V_n = -(B_nA)/t_n

V_n = \frac{-4BA}{(t/2)}\\\\V_n = \frac{-8BA}{t} \\\\V_n = 8V\\

The EMF has increased by a factor of 8.

5 0
2 years ago
A small block of mass 1.57 kg rests on the left edge of a block of length 3.45 m and mass 7.04 kg. the coefficient of kinetic fr
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2 years ago
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