Answer: In all cases, gravitational potential energy, respect from a common reference level (street level for instance) is the same.
Explanation:
Gravitational potential energy, comes from the action of the gravitational field, which is a conservative one.
This means, that if someone does work against the field (for instance lifting a weight from the ground to a given height), and then drops the weight, the work done by the field will be exactly the same.
Otherwise, the object would have remaining energy after returning to the starting point, which would violate the laws of physics, specially Thermodynamic's 2nd Law.
For this reason, the gravitational potential energy only depends from the height, and is independent from the path taken to reach there.
Answer:
Explanation:
Newton's law of universal gravitation states that the force experimented by a satellite of mass m orbiting Mars, which has mass 
at a distance r will be:
where 
is the gravitational constant.
This force is the centripetal force the satellite experiments, so we can write:
Putting all together:
which means:
![r=\sqrt[3]{\frac{GM}{4\pi^2}T^2}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7BGM%7D%7B4%5Cpi%5E2%7DT%5E2%7D)
Which for our values is:
![r=\sqrt[3]{\frac{(6.67\times10^{-11}Nm^2/kg^2)(6.39\times10^{23} kg)}{4\pi^2}(1.026\times24\times60\times60s)^2}=20395282m=20395.3km](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B%286.67%5Ctimes10%5E%7B-11%7DNm%5E2%2Fkg%5E2%29%286.39%5Ctimes10%5E%7B23%7D%20kg%29%7D%7B4%5Cpi%5E2%7D%281.026%5Ctimes24%5Ctimes60%5Ctimes60s%29%5E2%7D%3D20395282m%3D20395.3km)
Since this distance is measured from the center of Mars, to have the height above the Martian surface we need to substract the radius of Mars R=3389.5 km
, which leaves us with:
Like a grandfather clock,
A pendulum = a string with a weight(can be anything from a coin to a ring to a ball) is on the end, the pendulum swings back and forth losing a little bit of energy every swing until it comes to a complete stop
I did try to solve. I hope it is correct, below is the solution:
<span>put everything in s.i units
then the answer what u wrote is acceleration to get is divide by mass(80)
G=6.011*10^-11
M=6*10^24
R=6.4*10^6
m=80
</span>
Hope it helps.
