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Degger [83]
2 years ago
7

calculate the pressure exerted by a mercury column of 76 cm high at its bottom.Given that density of mercury is 13600kg/m^3 and

g=9.8​

Physics
1 answer:
Amanda [17]2 years ago
5 0

Answer:

Explanation:I don't say you have to mark my ans as brainliest but if you think it has really helped you plz don't forget to thank me ...

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SIZIF [17.4K]
C is the first & the second question is A
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3 years ago
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A waitperson carrying a tray with a platter on it tips the tray at an angle of 12 degrees below the horizontal. If the gravitati
Tasya [4]

Answer:1.04 N

Explanation:

Given

Gravitational Force on the Platter is 5 N

Tray makes an angle of \theta =12^{\circ}

This gravitational Force has components along and Perpendicular to Platter

Perpendicular Force W_p=W\cos \theta

W_p=5\times \cos 12=4.89 N

Along the Tray

W_{along}=W\sin \theta

W_{along}=5\times \sin 12=1.04 N

Thus 1.04 N is the magnitude of force that will cause Platter to slide down  

7 0
3 years ago
14. The design for a rotating spacecraft below consists of two rings. The outer ring with a radius of 30 m holds the living quar
Zolol [24]

Answer:

T= 11.0003s

Explanation:

From the question we are told that

The outer ring with a radius of 30 m

inner Gravity Approximately 9.80 m/s'

Outer Gravity Approximately 5.35 m/s.

Generally  the equation for centripetal force is given mathematically as

Centripetal acceleration enables Rotation therefore?

     \omega ^2 r =Angular\ acc

Considering the outer ring,

 \omega ^2 r = 9.8

  \omega ^2= \frac{9.8}{30}

 \omega = \sqrt{\frac{9.8}{30}}

 \omega= 0.571 rad/s

Therefore solving for  Period T

Generally the equation for solving Period T is mathematically given as

 T= \frac{2\pi}{\omega}

 T= \frac{2\pi}{0.571 rad/s}

 T= 11.0003s

5 0
3 years ago
A small child has a wagon with a mass of 10 kilograms. The child pulls on the wagon with a force of
Sholpan [36]
F=ma
where:
F - force
m - mass
a - acceleration 

We transform this formula to get a:
a= \frac{F}{m}
a=\frac{2}{10}\frac{N}{kg}=0.2\frac{m}{s^{2}}
4 0
3 years ago
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What are the characteristics of image when object is between f1 and 2f1 for concave lense?​
k0ka [10]

Answer:

The required diagram is shown in the figure. When an object is placed in front of the convex lens, i.e., between 2F

1

and F

1

, its image is formed beyond 2F

2

on the other side of the lens. The image is real, inverted and enlarged.

solution

5 0
3 years ago
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