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Gnesinka [82]
3 years ago
11

The discovery of what element showed the usefulness of Mendeleev’s periodic table?

Physics
2 answers:
lesya [120]3 years ago
7 0
A. Gallium

'cause he predicted it's physical properties before it's discovery! After that, it was proved that Mendeleev's periodic table was useful.

Hope this helps!
jekas [21]3 years ago
4 0
<h3><u>Answer;</u></h3>

A. Gallium

<h3><u>Explanation;</u></h3>
  • Mendeleev arranged the elements in rows in order of increasing mass so that elements with similar properties were in the same column.
  • <em><u>The discovery of new elements such as gallium demonstrated the usefulness of Mendeleev’s table because the close match between Mendeleev’s predictions and the actual properties of new elements showed how useful his periodic table could be. </u></em>
  • Mendeleev’s efforts more successful because he provided an organizing principle that worked for all off the known elements.


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The diffuser in a jet engine is designed to decrease the kinetic energy of the air entering the engine compressor without any wo
wariber [46]

Explanation:

Expression for energy balance is as follows.

        \Delta E_{system} = E_{in} - E_{out}

or,          E_{in} = E_{out}

Therefore,  

         m(h_{1} \frac{v^{2}_{1}}{2}) = m (h_{2} \frac{V^{2}_{2}}{2})

          h_{1} + \frac{V^{2}_{1}}{2} = h_{2} + \frac{V^{2}_{2}}{2}

Hence, expression for exit velocity will be as follows.

           V_{2} = [V^{2}_{1} + 2(h_{1} - h_{2})^{0.5}

                      = V^{2}_{1} + 2C_{p}(T_{1} - T_{2})]^{0.5}

As C_{p} for the given conditions is 1.007 kJ/kg K. Now, putting the given values into the above formula as follows.

       V_{2} = V^{2}_{1} + 2C_{p}(T_{1} - T_{2})]^{0.5}                    

                  = [(350 m/s)^{2} + 2(1.007 kJ/kg K) (30 - 90) K \frac{1000 m^{2}/s^{2}}{1 kJ/kg}]^{0.5}

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Thus, we can conclude that velocity at the exit of a diffuser under given conditions is 40.7 m/s.

5 0
3 years ago
2-The amount of internal energy needed to raise the temperature of 0.25kg of water by 0.2°C is 209.3 J. How fast must a 0.25 kg
Yakvenalex [24]

Answer:

40.92 m/s

Explanation:

The computation is shown below:

Ek = 1 ÷2mv²...............................(1)

v = √(2Ek/m).......................... (2)

Here EK denotes kinetic energy

m denotes mass

v denotes velocity

Given that

m = 0.25kg and Ek = 209.3J

So,

v = √(2×209.3 ÷0.25)

= √1674.4

= 40.92 m/s

7 0
3 years ago
Two objects, C &amp; D, have the same momentum. Object C has ½ the mass of object D. Find the value of the ratio of velocity C t
Savatey [412]
These are two questions and two answers.

Part 1. Fin the value of the ration of velocity C to velocity D.


Answer: 2

Explanation:

1) Formula: momentum = mass * velocity

2) momentum C = mass C * velocity C

3) momentum D = mass D * velocity D.

4) C and D have the same momentum =>

mass C * velocity C = mass D * velocity D

5) mass C = (1/2) mass D => mass C / mass C = 1/2

6) use in the equation stated in the point 4)

velocit C / velocity D = mass D / mass C

using the equation stated in point 5:

mass D / mass C = 1 / [ mass C / mass D] = 1 / [1/2] = 2

=>

7) velocity C / velocity D = mass D / mass C = 2

Part 2: <span>ratio of kinetic energy C to kinetic energy D.
</span>
Answer: 2

Explanation:

1) formula: kinetic energy KE = (1/2) mass * (velocity)^2

2) KE C = (1/2) mass C * (velocity C)^2

3) KE D = (1/2) mass D * (velocity D)^2

4) KE C / KE D =

(1/2) mass C * (velocity C)^2        mass C        (velocity C)^2
--------------------------------------- = --------------- * ---------------------- = (1/2) * (2)^2
(1/2) mass D *( velocity D)^2        mass D        v(velocity D)^2

= 4 / 2 = 2
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minim
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