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Korolek [52]
3 years ago
14

Một khối lập phương bằng nhôm cạnh 20cm nổi trên thuỷ ngân. Hỏi khối nhôm sẽ chìm xuống bao nhiêu khi nhiệt độ tăng từ 270K đến

320K (Hệ số nở khối của thuỷ ngân là 1,8.10^-4/ độ C)
Physics
1 answer:
Nady [450]3 years ago
7 0

Answer:

English or spanish please

Explanation:

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Um comentarista de futebol certa vez comentou:"A bola bateu na trave e voltou duas vezes mais forte". Sabendo que quando a bola
ryzh [129]

Answer:

Por ela ter batido na trave, não tem como voltar 2x mais forte, por que toda ação correspondente a uma reação de igual intensidade, mas que atua no sentido oposto

Explanation:

7 0
3 years ago
A(n) 93 kg clock initially at rest on a horizontal floor requires a(n) 610 N horizontal force to set it in motion. After the clo
denpristay [2]

Answer:0.669

Explanation:

Given

mass of clock 93 kg

Initial force required to move it 610 N

After clock sets in motion it requires a force of 514 N to keep moving it with a constant velocity

Initially static friction is acting which is more than kinetic friction

thus 613 force is required to overcome static friction

\mu _smg=610

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\mu _s=0.669

5 0
3 years ago
What do u put on the last blank?
Nookie1986 [14]

The greater the MASS of a moving object, the more kinetic energy it has. <3

8 0
3 years ago
How would a parachute fall on the surface of the moon ? Describe. The mass of the Jupiter is
GREYUIT [131]

Explanation:

the answer is 2.46 × 10^12

6 0
2 years ago
Is V directly proportional to I (From V=IR)??<br>Or is V inversely proportional to I (From P=IV) ???
ziro4ka [17]

First of all, I is proportional V according to the Ohm's Law. R is merely a constant you need to obtain an equation. However, it is true that R changes with temperature and pressure, therefore Ohm's Law is only applicable in an invariable environment. Also this constant R is different for different materials.

So, do not get confused.

Ohm's law is not a universal law, please remember that as well. Some materials do not follow it and we call them non-ohmic conductors. I hope I helped! ^-^

3 0
3 years ago
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