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zvonat [6]
3 years ago
11

Calculate the area

Mathematics
2 answers:
WINSTONCH [101]3 years ago
8 0

A=a\cdot b\cdot \sin\angle AB\\\\A=5\cdot8\cdot\sin63^\circ\\\\A=40\cdot0.891\\\\\boxed{A=35.64}

OLga [1]3 years ago
3 0

Answer:

\huge \boxed{\mathrm{35.64 \ units^2 }}

Step-by-step explanation:

The adjacent side lengths and an angle is given.

We need to find the height of the parallelogram.

A small right triangle is formed with an angle of 63 degrees and an hypotenuse of 5 units.

We can use trigonometric functions to solve for the height.

sin θ = opp/hyp

sin 63 = h/5

Multiplying both sides by 5.

h = 5 sin 63

h ≈ 4.45503262

Area of parallelogram = base × height

A = 8 × 4.45503262

A = 35.640261

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3 years ago
For all values of x
Yuliya22 [10]

Answer:

A.) gf(x) = 3x^2 + 12x + 9

B.) g'(x) = 2

Step-by-step explanation:

A.) The two given functions are:

f(x) = (x + 2)^2 and g(x) = 3(x - 1)

Open the bracket of the two functions

f(x) = (x + 2)^2

f(x) = x^2 + 2x + 2x + 4

f(x) = x^2 + 4x + 4

and

g(x) = 3(x - 1)

g(x) = 3x - 3

To find gf(x), substitute f(x) for x in g(x)

gf(x) = 3( x^2 + 4x + 4 ) - 3

gf(x) = 3x^2 + 12x + 12 - 3

gf(x) = 3x^2 + 12x + 9

Where

a = 3, b = 12, c = 9

B.) To find g '(12), you must first find the inverse function of g(x) that is g'(x)

To find g'(x), let g(x) be equal to y. Then, interchange y and x for each other and make y the subject of formula

Y = 3x + 3

X = 3y + 3

Make y the subject of formula

3y = x - 3

Y = x/3 - 3/3

Y = x/3 - 1

Therefore, g'(x) = x/3 - 1

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g'(x) = 12/4 - 1

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g'(x) = 2.

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3 years ago
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