First of all, you didn't tell us WHO measured the "10 years".
If it was the people on Earth, then 10 years passed according to them.
If it was 10 years on the space traveler's clock, then the clock in the
OTHER place, like on Earth, is subject to the relativistic 'time dilation'.
If the clocks are moving relative to each other, then the time interval measured
on either clock is equal to the interval measured on the other clock, divided by
√(1 - v²/c²) .
You said that v/c = 0.85 .
v²/c² = (0.85)² = 0.7225
1 - v²/c² = 1 - 0.7225 = 0.2775
√(1 - v²/c²) = √0.2775 = 0.5268
If one clock counts up 10 years, then the other one counts up
(10years) / 0.5268 = <em>18.983 years </em>
I believe that's the way to do this, and I'll gladly take your points,
but let me recommend that you get a second opinion before you
actually take off on your 10-year interstellar mission.
The activation energy is lowered only
There are more collisions per second and the collisions are of greater energy
There are more collisions per second only
The activation energy is lowered
Answer:
The final speed of the train and Bambi after collision is 7.44 m/s
Explanation:
Given;
mass of the train, m₁ = 1000kg
mass of Bambi, m₂ = 75kg
initial speed of the train, u₁ = 8 m/s
initial speed of Bambi, u₂ = 0 m/s
If Bambi gets stuck to the front of the train, then the collision is inelastic.
m₁u₁ + m₂u₂ = v(m₁ + m₂)
where;
v is the final speed of the train and Bambi after collision
Substitute the given values and solve for v
1000 x 8 + 75 x 0 = v (1000 + 75)
8000 = v (1075)
v = 8000/1075
v = 7.44 m/s
Therefore, the final speed of the train and Bambi after collision is 7.44 m/s
Answer:
A uniform meter rule of mass 100 g is balanced on a fulcrum at mark 40 cm by suspending an unknown mass m at the mark 20 cm. ... When the balancing mass is moved then the resultant moment is the difference of clockwise moment and anticlockwise moment.
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