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Goryan [66]
3 years ago
14

A 2kg 2 kg object is moving in along the x x -axis under a single conservative force. When the object is at position x=0 x = 0 ,

its speed is 3ms 3 m s . The potential energy U U associated with the conservative force is given as a function of x x by the equation U=αx2 U = α x 2 , where α=4Nm α = 4 N m . Which of the following is correct about the motion of the object?
Physics
1 answer:
Luden [163]3 years ago
7 0

Answer:

The particle comes to rest before reaching the position x=4m.

Explanation:

When the object is at x=0m, all of its energy is kinetic energy. Using the equation for kinetic energy yields KE=1/2mv^2=(12)(2)(3)^2=9J. Using the given equation for potential energy when the object is at x=4m yields U=4x^2=4(4)^2=64J. Since the system only has 9J of energy, the object comes to rest before reaching x=4m.

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SI Prefix Meaning
LenKa [72]
- deci: one-tenth.
- centi: one-hundredth.
- nano: one-billionth.

hope this helps :)
7 0
3 years ago
If the accuracy in measuring the position of a particle increases, what happens to the accuracy in measuring its velocity? - The
timofeeve [1]

Answer:

- The accuracy in measuring its velocity decreases.

Explanation:

This can be explained by Heisenberg's uncertainty principle which states that the position and velocity of a particle can be determined together exactly in reality.

This principle, unlike Newtonian mechanics deal with particles at microscopic level like that of an electron where if the accuracy in measurement of particle's position increases there will be  decreased accuracy in measurement of velocity of that particle.

There will be an uncertainty in accuracy in the measurement of particle's position and its velocity.

5 0
3 years ago
If the bat emits a sound at a frequency of 80.2 kHzkHz and hears it reflected at a frequency of 83.5 kHzkHz while traveling at a
solong [7]

To solve this problem we will apply the concepts related to the Doppler Effect. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other.

Mathematically it can be described as

v' = v (\frac{f' ( v - v_{bat}) - f ( v + v_{bat})}{f'(v-v_{bat}) + f ( v + v_{bat})})

Where,

v = Speed of sound

f' = Reflected frequency

f = Emitted Frequency

v_{bat} = Speed of the object

Assuming that the speed of the medium is the speed of sound of 343m / s, we will then have that:

v' = 343 (\frac{(83.5) (343 -3.9) - 80.2(343+3.9)}{83.5(343-3.9) + 80.2(343+4.3)})

v' = 3.0134m/s

8 0
4 years ago
All else equal, the payback period for a project will decrease whenever the_______.
telo118 [61]

Answer:

(B) cash inflows are moved earlier in time.

Explanation:

The payback period stated time-frame during which the initial amount of investment should be recovered. It is expressed in the year form

The formula to compute the payback period is shown below:

Payback period = Initial investment ÷ Net cash flow

where,  

The net cash flow = annual net operating income + depreciation expenses

The payback period of the project decreases when the accumulated starting year cash flows increases that results the movement of the cash inflows earlier in time

3 0
3 years ago
Read 2 more answers
Find average speed when time= 27s and total distance is 94m
Slav-nsk [51]
3.4814815 (or 3 13/27) m/s

speed = distance/time
3.4814815 (or 3 13/27) = 94/27

8 0
3 years ago
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