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Goryan [66]
3 years ago
14

A 2kg 2 kg object is moving in along the x x -axis under a single conservative force. When the object is at position x=0 x = 0 ,

its speed is 3ms 3 m s . The potential energy U U associated with the conservative force is given as a function of x x by the equation U=αx2 U = α x 2 , where α=4Nm α = 4 N m . Which of the following is correct about the motion of the object?
Physics
1 answer:
Luden [163]3 years ago
7 0

Answer:

The particle comes to rest before reaching the position x=4m.

Explanation:

When the object is at x=0m, all of its energy is kinetic energy. Using the equation for kinetic energy yields KE=1/2mv^2=(12)(2)(3)^2=9J. Using the given equation for potential energy when the object is at x=4m yields U=4x^2=4(4)^2=64J. Since the system only has 9J of energy, the object comes to rest before reaching x=4m.

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Answer:

A block device is a computer data storage device that supports reading and (optionally) writing data in fixed-size blocks, sectors, or clusters. These blocks are generally 512 bytes or a multiple thereof in size

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A spring has a force constant of525.6 N/m. Find the potential energy stored in thespring when thespring is...
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B compressed 2.17 cm from equilibrium. Answer in units of j
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3 years ago
If the coefficient of friction is 0.3900 and the cylinder has a radius of 2.700 m, what is the minimum angular speed of the cyli
Aleks04 [339]

Answer:

w=3.05 rad/s or 29.88rpm

Explanation:

k = coefficient of friction = 0.3900

R = radius of the cylinder = 2.7m

V = linear speed of rotation of the cylinder

w = angular speed = V/R or to rewrite V = w*R

N = normal force to cylinder

N==\frac{m(V)^{2}}{R}=m*(w)^2*R

Friction force\\Ff = k*N\\Ff= k*m*w^2*R

Gravitational force \\Fg = m*g

These must be balanced (the net force on the people will be 0) so set them equal to each other.

Fg = Ff

m*g = k*m*w^2*R

g=k*w^{2}*R

w^2 =\frac{g}{k*R}

w=\sqrt{\frac{g}{k*R}} \\w =\sqrt{\frac{9.8\frac{m}{s^{2}}}{0.3900*2.7m}}\\ w=\sqrt{9.306}=3.05 \frac{rad}{s}

There are 2*pi radians in 1 revolution so:

RPM=\frac{w}{2\pi }*60\\RPM=\frac{3.05\frac{rad}{s}}{2\pi}*60\\RPM= 0.498*60\\RPM=29.88

So you need about 30 RPM to keep people from falling out the bottom

7 0
4 years ago
Which of the following is not dimensionally correct?<br> E=mc2 B. vf=vi+at<br> S=vt2 D. S=1/2 at2
Elodia [21]

Answer:

s=vt2 just simplify all into metric units first

5 0
3 years ago
What potential difference would an electron have to fall through to acquire a speed of 3.00*10^6 m/sec?
kirill [66]

Answer:

25.6 V

Explanation:

The kinetic energy of electron associated with its potential difference is given by eV which is equal to the 1/2 mv^2.

m = 9.1 x 10^-31 kg, v = 3 x 10^6 m/s, e = 1.6 x 10^-19 C

eV = 1/2 m v^2

V = mv^2 / 2 e

V = (9.1 x 10^-31) x (3 x 10^6)^2 / (2 x 1.6 x 10^-19)

V = 25.6 V

4 0
4 years ago
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