Explanation:
q = mCΔT
where q is heat,
m is mass,
C is specific heat capacity,
and ΔT is temperature change.
For the first ball:
2500 J = (100 g) C (90°C − 25°C)
C = 0.385 J/g/°C
For the second ball:
5000 J = (200 g) C (90°C − 25°C)
C = 0.385 J/g/°C
The two metals have the same specific heat, and are likely the same metal (possibly copper or zinc).
Correct answer choice is:
C. Medium range
Explanation:
Medium range exercises are used to gain extra strength and fitness. Usually, heavyweights are used with less number of repetitions. These sort of exercises are mostly the hardest t do. All you need is to have a high level of motivation and stamina, which can be gained by running or cycling.
A projectile fired upward from the Earth's surface will usually slow down, come momentarily to rest, and return to Earth. For a certain initial speed, however it will move upward forever, with its speed gradually decreasing to zero just as its distance from Earth approaches infinity. The initial speed for this case is called escape velocity. You can find the escape velocity v for the Earth or any other planet from which a projectile might be launched using conservation of energy. The projectile of mass m leaves the surface of the body of mass M and radius R with a kinetic energy Ki = mv²/2 and potential energy Ui = -GMm/R. When the projectile reaches infinity, it has zero potential energy and zero kinetic energy since we are seeking the minimum speed for escape. Thus Uf = 0 and Kf = 0. And from conservation of energy,
Ki + Ui = Kf + Uf
mv²/2 -GMm/R = 0
∴ v = √(2GM/R)
This is the expression for escape velocity.
Answer:
the name of the SI unit for force is the newton
Answer:
Explanation:
Let's use the equation that relate the temperatures and volumes of an adiabatic process in a ideal gas.
.
Now, let's use the ideal gas equation to the initial and the final state:
Let's recall that the term nR is a constant. That is why we can match these equations.
We can find a relation between the volumes of the initial and the final state.
Combining this equation with the first equation we have:
Now, we just need to solve this equation for T₂.
Let's assume the initial temperature and pressure as 25 °C = 298 K and 1 atm = 1.01 * 10⁵ Pa, in a normal conditions.
Here,
Finally, T2 will be:
