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Kryger [21]
3 years ago
15

Can someone answer all of the questions?

Physics
2 answers:
Katyanochek1 [597]3 years ago
8 0

Answer: -200

Explanation: is it math

Veronika [31]3 years ago
3 0

Answer:

yeah but which one are u asking for

You might be interested in
Please help on questions D AND E and please show working out as well so I can understand better thank you only QUESTIONS D AND E
tester [92]

Answer:

d. 87,500 J

e. 49,600 J

Explanation:

The total energy is the heat absorbed by the copper plus the heat absorbed by the water.

d)

E = m₁C₁ΔT + m₂C₂ΔT

E = (1 kg) (390 J/kg/°C) (10 °C) + (2 kg) (4180 J/kg/°C) (10 °C)

E = 87,500 J

e)

E = m₁C₁ΔT + m₂C₂ΔT

E = (2 kg) (390 J/kg/°C) (10 °C) + (1 kg) (4180 J/kg/°C) (10 °C)

E = 49,600 J

5 0
3 years ago
A 2.0-mm-diameter copper ball is charged to 40 nC . What fraction of its electrons have been removed? The density of copper is 8
murzikaleks [220]

Answer:

0.02442 × 10⁻⁹

Explanation:

Given:

Diameter of copper ball = 2.00 mm = 0.002 m

Charge on ball = 40 nC = 40 × 10⁻⁹ C

Density of copper = 8900 Kg/m³

Now,

The number of electrons removed, n = \frac{\textup{Charge on ball}}{\textup{Charge of an electron}}

also, charge on electron = 1.6 × 10⁻¹⁹ C

Thus,

n = \frac{40\times10^{-9}}{1.6\times10^{-19}}

or

n = 25 × 10¹⁰ Electrons

Now,

Mass of copper ball = volume × density

Or

Mass of copper ball =  \frac{4}{3}\pi(\frac{d}{2})^3  × 8900

or

Mass of copper ball =  \frac{4}{3}\pi(\frac{0.002}{2})^3  × 8900

or

Mass of copper ball = 0.03726 grams

Also,

molar mass of copper = 63.546 g/mol

Therefore,

Number of mol of copper in  0.03726 grams = \frac{ 0.03726}{63.546}

or

Number of mol of copper in  0.03726 grams = 5.86 × 10⁻⁴ mol

and,

1 mol of a substance contains = 6.022 × 10²³ atoms

Therefore,

5.86 × 10⁻⁴ mol of copper contains = 5.86 × 10⁻⁴ × 6.022 × 10²³ atoms.

or

5.86 × 10⁻⁴ mol of copper contains = 35.88 × 10¹⁹ atoms

Now,

A neutral copper atom has 29 electrons.  

Therefore,

Number of electrons in ball = 29 × 35.88 × 10¹⁹ = 1023.37 × 10¹⁹ electrons.

Hence,

The fraction of electrons removed = \frac{25\times10^{10}}{1023.37\times10^{19}}

or

The fraction of electrons removed = 0.02442 × 10⁻⁹

3 0
4 years ago
A runner changing speed from 3 meters per second to 5 meters per second is an example of
Sidana [21]

Answer: acceleration

Explanation:

he is accelarting from 3 meters per second to 5 meters per second

4 0
3 years ago
At time t = 0 a car has a velocity of 16 m/s. It slows down with an acceleration given by
Leni [432]

Answer:

B

Explanation:

We know the inital velocity is 16 m/s

Acclereation is -0.5 m/s^2

And that final velocity is 0

We need to find time

v _{f} = v _{i} + at

0 = 16 + ( - 0.5)t

- 16 =  - 0.5t

32 = t

The answer is B

7 0
3 years ago
A substance with a define shape and volume is a
Vlad1618 [11]
Solid is the answer.
8 0
4 years ago
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