Answer:
Explanation:
Given:
- mass of the object,
- elastic constant of the connected spring,
- coefficient of static friction between the object and the surface,
(a)
Let x be the maximum distance of stretch without moving the mass.
<em>The spring can be stretched up to the limiting frictional force 'f' till the body is stationary.</em>
where:
N = m.g = the normal reaction force acting on the body under steady state.
(b)
Now, according to the question:
- Amplitude of oscillation,
- coefficient of kinetic friction between the object and the surface,
Let d be the total distance the object travels before stopping.
<em>Now, the energy stored in the spring due to vibration of amplitude:</em>
<u><em>This energy will be equal to the work done by the kinetic friction to stop it.</em></u>
<em>is the total distance does it travel before stopping.</em>
Answer:
potential energy decreases
kinetic energy increases
The magnitude of 33 i + 15 j is
√ (33² + 15²)
= √ (1089 + 225)
= √ 1314 = 36.25 (rounded)
F=ma
=> 20=10m so m=2
Then the force is doubled 20.2=40
F'=ma'
m does not change so 40=2.a'
a'=20 which is option b.
Give a brainliest please:-)