Answer:

Explanation:
<u>Mechanical Force</u>
According to the second Newton's law, the net force F exerted by an external agent on an object of mass m is:
F = m.a
Where a is the acceleration of the object.
Assume we apply some given force F to an object of m1=1 Kg that produces an acceleration
, then:
F = m1.a1
The same force F is now applied to a second object m2=4 Kg that produces an acceleration a2, then:
F = m2.a2
Dividing both equations:

Solving for a2:

Substituting values:


Answer:
1.28 m
Explanation:
Generally, pressure of fluid is given by
where g is acceleration due to gravity, h is the height and
is the density
Considering that the pressure for mercury is same as for blood only that the height and density of fluid are different then
Since g is constant, then
Making
the subject of the formula then

Where subscripts m and b denote mercury and blood respectively
Assuming density of blood is 1060 Kg/m3, density of mercury as 13600 Kg/m3 and substituting height of mercury for 0.1 m then

The solution for this problem would be:(10 - 500x) / (5 - x)
so start by doing:
x(5*50*2) - xV + 5V = 0.02(5*50*2)
500x - xV + 5V = 10
V(5 - x) = 10 - 500x
V = (10 - 500x) / (5 - x)
(V stands for the volume, but leaves us with the expression for x)
By definition,
q = 1.22y/D
Where,
q = min. angle
y = wavelength
D = Aperture diameter = diameter of the antenna
At distance "x" from the antenna,
L =xq = 1.22xy/D
Where, L = Min. distance
But, y =c/f = (3*10^8)/(16*10^9) = 0.01875 m
Substituting;
L = 1.22*5*10^3*0.01875/2.1 = 54.46 m
Answer:
its most definitely c. trust me
Explanation: