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Luden [163]
4 years ago
6

5. For what purpose do bats use ultrasonic waves?

Physics
1 answer:
Hunter-Best [27]4 years ago
4 0

Answer:

Doppler effect

Explanation:

because it uses that to catch it's prey

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A car is traveling to the right with a speed of 2.0 m/s on an icy road when the brakes are applied. The car begins sliding with
quester [9]

Answer:

t = 3.0s

Explanation:

U = 2.0m/s , V = 0 (stop) , S = 3m , t =?

From V^2 - U^2 = 2aS

=) a = -4/6 = -0.667m/s^2

Now again by V-U = at

We have t = -U/a = 2/0.667 = 3s

Required time is t = 3.0s

6 0
3 years ago
A thin stream of water flows vertically downward. the stream bends toward a positively charged object when it is placed near it.
vfiekz [6]
I dont know the answer i just want brainy points<span />
5 0
3 years ago
In this reaction diagram which part represents the doffrence in energy between the reactants and the products?
Annette [7]

Answer:

The correct answer is - option C. G.

Explanation:

In this reaction diagram, there is a representation of the reaction profile. The reaction profile shows the change that takes place during a reaction in the energy of reactants or substrate and products. In this profile, activation energy looks like a hump in the line, and the minimum energy required to initiate the reaction.

The overall energy of the reaction, including or excluding activation energy depends on the nature of the reaction if it is exothermic or endothermic. and products are represented by the G which shows the difference between the energy of the reactants and products.

3 0
3 years ago
Read 2 more answers
what is the result of 6.2×10 to the fourth power times 3.3×10 to the second power express in scientific notation
Maslowich
2.046x10^7 or 2.046x10^6
4 0
4 years ago
fuel was consumed at a certain rate of 0.05Kg\s in a rocket engine and ejected as a gas with a speed of4000m\s . Determine the t
ivann1987 [24]

Answer:

Thrust = 200 N

Explanation:

The engine thrust can be found by using the following formula:

Thrust = mv

where,

m = mass flow rate of the fuel = 0.05 kg/s

v = velocity of ejected gases = 4000 m/s

Therefore, using the given values in the equation, we get:

Thrust = (0.05\ kg/s)(4000\ m/s)

<u>Thrust = 200 N</u>

5 0
3 years ago
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