Answer:
S = V t where S is the horizontal distance traveled
1/2 g t^2 = H where H is the vertical distance traveled
t^2 = 2 H / g
V^2 = S^2 / t^2 = S^2 g / (2 H) combining equations
tan theta = H / S
V^2 = S g / (2 tan theta)
Using S = L cos theta
V^2 = L g cos theta / (2 tan theta)
Giving V in terms of L and theta
A is an example of physical change
Answer:
<u>40 m/s</u>
Explanation:
The final velocity of an object that experiences a period of acceleration is given by:
v - vi = A*t
Initial velocity, vi, is = 20m/s
Acceleration, A, is 4m/2^2
Time, t, is 5 seconds
v - vi = A*t
v - 20m/s = (4m/2^2)/(5 sec)
v = (20 m/s) + (20 m/s)
v = 40 m/s
Answer:
0.25714 m/s
Explanation:
= Mass of 45 kg skater
= Mass of 60 kg skater
= Speed of 45 kg skater
= Speed of 60 kg skater
As the momentum is conserved
= Relative speed = 0.6 m/s
The speed of the 60kg skater is 0.25714 m/s
