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juin [17]
2 years ago
11

Singing that is off-pitch by more than about 1% sounds bad. How fast would a singer have to be moving relative to the rest of a

band to make this much of a change in pitch due to the Doppler effect
Physics
1 answer:
Nina [5.8K]2 years ago
3 0

Answer:

-3.396 m/s or 3.465 m/s

Explanation:

v = Speed of sound in air = 343 m/s

v_s = Relative speed of the singer

f = Observed frequency

f' = Actual frequency

1% change can mean f=1.01f'

From the Doppler effect equation we have

f=f'\dfrac{v}{v+v_s}\\\Rightarrow 1.01f'=f'\dfrac{v}{v+v_s}\\\Rightarrow 1.01=\dfrac{343}{343+v_s}\\\Rightarrow v_s=\dfrac{343}{1.01}-343\\\Rightarrow v_s=-3.396\ m/s

The velocity is -3.396 m/s

when f=0.99f'

f=f'\dfrac{v}{v+v_s}\\\Rightarrow 0.99f'=f'\dfrac{v}{v+v_s}\\\Rightarrow 0.99=\dfrac{343}{343+v_s}\\\Rightarrow v_s=\dfrac{343}{0.99}-343\\\Rightarrow v_s=3.46464646465\ m/s

The velocity is 3.465 m/s

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Answer:

1.045 m from 120 kg

Explanation:

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Let m is placed at a distance y from 120 kg so that the net force on 51 kg is zero.

By use of the gravitational force

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\frac{Gm_{1}m}{y^{2}}=\frac{Gm_{2}m}{\left ( d-y \right )^{2}}

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Thus, the net force on 51 kg is zero if it is placed at a distance of 1.045 m from 120 kg.

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