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juin [17]
3 years ago
11

Singing that is off-pitch by more than about 1% sounds bad. How fast would a singer have to be moving relative to the rest of a

band to make this much of a change in pitch due to the Doppler effect
Physics
1 answer:
Nina [5.8K]3 years ago
3 0

Answer:

-3.396 m/s or 3.465 m/s

Explanation:

v = Speed of sound in air = 343 m/s

v_s = Relative speed of the singer

f = Observed frequency

f' = Actual frequency

1% change can mean f=1.01f'

From the Doppler effect equation we have

f=f'\dfrac{v}{v+v_s}\\\Rightarrow 1.01f'=f'\dfrac{v}{v+v_s}\\\Rightarrow 1.01=\dfrac{343}{343+v_s}\\\Rightarrow v_s=\dfrac{343}{1.01}-343\\\Rightarrow v_s=-3.396\ m/s

The velocity is -3.396 m/s

when f=0.99f'

f=f'\dfrac{v}{v+v_s}\\\Rightarrow 0.99f'=f'\dfrac{v}{v+v_s}\\\Rightarrow 0.99=\dfrac{343}{343+v_s}\\\Rightarrow v_s=\dfrac{343}{0.99}-343\\\Rightarrow v_s=3.46464646465\ m/s

The velocity is 3.465 m/s

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Answer:

The value is  x = 11.81 \ m

Explanation:

From the question we are told that

   The height is h =  2.0 m

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    The initial velocity of the rock is u =  20 \ m/s

    The angle at which it is thrown is \theta  =  40

Generally the  vertical component of the velocity of the stone is mathematically represented as

    v_y = 20 sin (40)

=>v_y = 12.86 \ m/s

Generally the height of the window from the ground is mathematically represented as using kinematic equation as

      d = h  +  v_yt + \frac{1}{2} gt^2

=>   9 = 2  +12.86 t + \frac{1}{2} * - 9.8 t^2

Here g is negative -9.8 m/s^2 because the direction of the stone is against gravity

   So

       4.9 t^2 -12.86 t + 7 =0

Solving this quadratic equation using quadratic formula we obtain

     t = 0.770 s

Generally the velocity of the stone on the x axis is mathematically represented as

       v_x =  20 * cos(40 )

=>    v_x =  15.32 \  m/s

Generally the distance between the person throwing the rock and the window is mathematically represented as

       x =  v_x * t

=>    x =  15.32 * 0.771

=>    x = 11.81 \ m

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Four main types of resistant forces
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The force of air resistance acts to oppose the motion of an object moving through the air. A ball is thrown upward and eventuall
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Answer:

For a (1) net force will be greater than the weight of the ball

For b (2) net force will be lesser than the weight of the ball

Explanation:

For (a):

For a linear motion of a system, one must have to understand, according to Newtons first law of motion, which is also known as law of inertia, a body which is at motion will continue to move or a body at rest will continue to rest until an external force is applied to it. In the given case, when ball goes upward, one thing is for sure, the net force is greater than the weight of the ball, because three forces are applied during upward motion:

gravity or weight which is pulling the ball downward,

air resistance, which is also acting downward as it is creating friction between ball and air molecules, so creating hindrance in upward motion

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Net Force = Upward force - Air friction - Weight

Since ball is going upward, so net force is greater than both weight and air friction which are pulling ball downward.

For (b):

For a linear motion of a system, one must have to understand, according to Newtons first law of motion, which is also known as law of inertia, a body which is at motion will continue to move or a body at rest will continue to rest until an external force is applied to it. In the given case, when ball goes downward, one thing is for sure, the net force is lesser than the weight of the ball, because two forces are applied during downward motion:

gravity or weight which is pulling the ball downward,

air resistance, which is acting upward as it is creating friction between ball and air molecules, so creating hindrance in downward motion

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Net Force = Weight - Air friction

Since ball is going downward, so weight is greater than net force which is in this case is air friction which is pulling ball upward.

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