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3 years ago

What was the kickball was originally named

Physics

2 answers:

Misha Larkins [42]3 years ago

5 0

Answer:

kick baseball

Explanation:

The sport of kickball, originally called "kick baseball," has roots going back to the early part of the 20th century in Cincinnati, Ohio. In the 1920's physical education teachers used kickball to teach the basics of baseball

Serggg [28]3 years ago

5 0

When it was originally invented, it was known as “kick baseball”. A few years later, kickball was adopted into the curriculum of education by physical education teachers nationwide, as an introduction to playing the most American sport of them all – baseball.

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Sound energy cannot travel through <br> A vacuum,a wooden table,polluted air,pond water

FromTheMoon [43]

Sound energy cannot travel through a vacuum.

Explanation:

Waves are periodic disturbance of the space, which travel carrying energy but not matter.

There are two types of waves:

Mechanical waves: mechanical waves propagate through the vibrations of the particles in a medium. Examples of mechanical waves are sound waves.
Electromagnetic waves: these waves consist of periodic oscillations of electric and magnetic fields, perpendicular to each other. These waves do not need a medium to propagate, so they can also travel in a vacuum.

In this problem, we are analyzing sound energy, which is the energy carried by sound waves. Sound waves are mechanical waves, so they need a medium to propagate: therefore, they cannot travel through a vacuum, since there is no medium.

So, sound energy cannot travel through a vacuum.

Learn more about waves:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

6 0

3 years ago

Find the mass. 10 points. Will give brainliest.

TiliK225 [7]

Answer:

Explanation:

Given,

Force ( f ) = 30 N

Acceleration(a) = 7.6 m/s

Now, Let's find the mass of the ball

Using the Newton's second law of motion:

We get:

$force \: = mass \: \times acceleration$

plug the value

$30 \: = m \: \times 7.6$

Use the commutative property to reorder the terms

$30 = 7.6 \: m$

Swap the sides of the equation

$7.6m = 30$

Divide both sides of the equation by 7.6

$\frac{7.6 \: m}{7.6} = \frac{30}{7.6}$

Calculate

$m = 3.94 \: kg$

Hope this helps..

Best regards!!

7 0

3 years ago

Read 2 more answers

An electric ceiling fan is rotating about a fixed axis with an initial angular velocity magnitude of 0.300 rev/s . The magnitude

Salsk061 [2.6K]

1) 1.2 m/s

First of all, we need to find the angular velocity of the blade at time t = 0.200 s. This is given by

$\omega_f = \omega_i + \alpha t$

where

$\omega_i = 0.300 rev/s$ is the initial angular velocity

$\alpha = 0.895 rev/s^2$ is the angular acceleration

Substituting t = 0.200 s, we find

$\omega_f = 0.300 + (0.895)(0.200)=0.479 rev/s$

Let's now convert it into rad/s:

$\omega_f = 2\pi \cdot 0.479 rev/s=3.01 rad/s$

The distance of a point on the tip of the blade is equal to the radius of the blade, so half the diameter:

$r=\frac{0.800}{2}=0.400 m$

And so now we can find the tangential speed at t = 0.200 s:

$v=\omega_f r =(3.01)(0.400)=1.2 m/s$

2) $2.25 m/s^2$

The tangential acceleration of a point rotating at a distance r from the centre of the circle is

$a_t = \alpha r$

where $\alpha$ is the angular acceleration.

First of all, we need to convert the angular acceleration into rad/s^2:

$\alpha = 0.895 rev/s^ \cdot 2 \pi =5.62 rad/s^2$

A point on the tip of the blade has a distance of

r = 0.400 m

From the centre; so, the tangential acceleration is

$a_t = (5.62)(0.400)=2.25 m/s^2$

3) $3.6 m/s^2$

The centripetal acceleration is given by

$a=\frac{v^2}{r}$

where

v is the tangential speed

r is the distance from the centre of the circle

We already calculate the tangential speed at point a):

v = 1.2 m/s

while the distance of a point at the end of the blade from the centre is

r = 0.400 m

Therefore, the centripetal acceleration is

$a=\frac{1.2^2}{0.400}=3.6 m/s^2$

7 0

3 years ago

3 ways how natural disasters impact environment.

Trava [24]

1. When sewage treatment plants flood or debris reaches reservoirs and streams, the quality of the water is affected.

2. Storm surges cause beaches to shift and alter shape.

3. During flash floods, riverbanks erode.

5 0

2 years ago

In the design of wall and column forms, the two most important factors are which of the following? a. rate of placement of the c

Simora [160]

Answer:

c. length of the wall or column and the rate of placement of the concrete

Explanation:

when designing for wall and column form-works, it is of utmost important to know the length of the wall and the type of concrete placement to be used.

Concrete placement has methods and precaution to be taken when doing the form work

if the concrete placement is manually (hand or funnel) the form work height should not be more than 1 m to enable easy compaction and vibration of concrete in the form.

Also, if the form work length is too long and it is not well reinforced, it tends to burg if the force apply during concrete placement or during vibration is much.

5 0

3 years ago