What is the magnitude of the force between two parallel wires 43.0 m long and 5.9 cm apart, each carrying 35.0 A in the same dir
1 answer:
Answer:
The magnitude of the force between the two wires is
Explanation:
If there are two parallel rectilinear conductors through which two electric currents of the same direction I1 and I2 circulate,both conductors will generate a magnetic field on each other, giving rise to a force between them.
To calculate the value of this force, first, according to the law of Biot and Savart, the magnetic field produced by conductor 1 over 2 is obtained, which will be given by the equation:
B1= equation 1
B1: Magnetic field produced by conductor 1
= free space permeability
a= distance between wires
I1= current carrying wire 1
This magnetic field exerts on a segment L of the conductor 2 through which a current of intensity I2 circulates, a force equal to:
F1-2= I2*L*B1 Equation2
We replaced B1 of the equation 1 in the equation 2:
F1-2=
F1-2=
If we calculate the force exerted by conductor 2 on conductor 1 we would arrive at exactly the same value:
F2-1= F1-2
For this problem, the magnitude of the force between the two parallel cables that conduct current in the same direction is:
F1-2=F2-1=F
Wb/A.m
I1=I1=35A
L=43M
a =5.9 cm= m
Answer: The magnitude of the force between the two wires is
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1 kg ball can have more kinetic energy than a 100 kg ball as increase in velocity is having greater impact on K.E than increase in mass.
<u>Explanation</u>:
We know kinetic energy can be judged or calculated by two parameters only which is mass and velocity. As kinetic energy is directly proportional to the and increase in velocity leads to greater effect on translational Kinetic Energy. Here formula of Kinetic Energy suggests that doubling the mass will double its K.E but doubling velocity will quadruple its velocity:
Better understood from numerical example as given:
If a man A having weight 50 kg run with speed 5 m/s and another man B having 100 kg weight run with 2.5 m / s. Which man will have more K.E?
This can be solved as follows:
It shows that man A will have more K.E.
Hence 1 kg ball can have more K.E than 100 kg ball by doubling velocity.
Explanation:
The 11Ω, 22Ω, and 33Ω resistors are in parallel. That combination is in series with the 4Ω and 10Ω resistors.
The net resistance is:
R = 4Ω + 10Ω + 1/(1/11Ω + 1/22Ω + 1/33Ω)
R = 20Ω
Using Ohm's law, we can find the current going through the 4Ω and 10Ω resistors:
V = IR
120 V = I (20Ω)
I = 6 A
So the voltage drops are:
V = (4Ω) (6A) = 24 V
V = (10Ω) (6A) = 60 V
That means the voltage drop across the 11Ω, 22Ω, and 33Ω resistors is:
V = 120 V − 24 V − 60 V
V = 36 V
So the currents are:
I = 36 V / 11 Ω = 3.27 A
I = 36 V / 22 Ω = 1.64 A
I = 36 V / 33 Ω = 1.09 A
If we wanted to, we could also show this using Kirchhoff's laws.
