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olga55 [171]
3 years ago
8

Read this excerpt from Emerson’s essay “Self-Reliance” and decide whether it is biased. Explain your answer as well as what you

can conclude from this excerpt.
To believe your own thought, to believe that what is true for you in your private heart is true for all men,—that is genius. . . Familiar as the voice of the mind is to each, the highest merit we ascribeto assign; credit to Moses, Plato, and Milton is, that they set at naughtnone; no books and traditions, and spoke not what men, but what they thought. A man should learn to detect and watch that gleam of light which flashes across his mind from within. . . . Yet he dismisses without notice his thought, because it is his. In every work of genius we recognize our own rejected thoughts: they come back to us with a certain alienated majesty.
Chemistry
1 answer:
nadezda [96]3 years ago
3 0

Answer:

In this excerpt, Emerson is in favor of, and stresses the importance of, individual intellect and moral development. He urges readers to look within—into their inner selves to seek inspiration and attain self-reliance rather than imitating others or adopting age-old ideas, which society has practiced over time. He uses examples of great thinkers such as Moses, Milton, and Plato, who thought for themselves and didn’t let society and established ideas influence them. Emerson further stresses that people should not dismiss their own ideas, only to discover them in others’ works, but learn to nurture and accept their potential. When people are able to accept and trust their own thoughts, they will be able to come up with ideas as brilliant and original as those of any wise man.

Explanation:

Hope this helps.

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Explain how you would calculate the q for warming 100.0 grams of liquid water from 0°C to 100 °C.
mojhsa [17]

Answer:

mass = 100 g

T1 = 0°C

T2 = 100 °C

C = 1 cal/g°C

Q = mC(T2 -T1)

Q = 100(1)(100 - 0)

Q = 100(100)

Q = 10000 cal

Explanation:

6 0
3 years ago
Name the following compounds: carbon (IV) fluorine
aalyn [17]
CF4 is the chemical equation of the compound

6 0
4 years ago
Grinding quartz crystals down to produce sand is an example of a
Katyanochek1 [597]
Grinding quartz crystals down to produce sand is an example of a?

-physical change
5 0
3 years ago
Calculate the pH of a solution that contains 2.7 M HF and 2.7 M HOC6H5. Also, calculate the concentration of OC6H5- in this solu
borishaifa [10]

Answer:

\large \boxed{\mathbf{1.36; 3.6 \times 10^{\mathbf{-9}}}\textbf{mol/L}}

Explanation:

The HF is about five million times as strong as phenol, so it will be by far the major contributor of hydronium ions. We can ignore the contribution from the phenol.

1 .Calculate the hydronium ion concentration

We can use an ICE table to organize the calculations.

                    HF + H₂O ⇌ H₃O⁺ + F⁻

I/mol·L⁻¹:       2.7                   0       0

C/mol·L⁻¹:      -x                   +x      +x

E/mol·L⁻¹:   2.7 - x                 x        x

K_{\text{a}} = \dfrac{\text{[H}_{3}\text{O}^{+}] \text{F}^{-}]} {\text{[HF]}} = 7.2 \times 10^{-4}\\\\\dfrac{x^{2}}{2.7 - x} = 7.2 \times 10^{-4}\\\\\text{Check for negligibility of }x\\\\\dfrac{2.7}{7.2 \times 10^{-4}} = 4000 > 400\\\\\therefore x \ll 2.7\\\dfrac{x^{2}}{2.7} = 7.2 \times 10^{-4}\\\\x^{2} = 2.7 \times 7.2 \times 10^{-4} = 1.94 \times 10^{-3}\\x = 0.0441\\\text{[H$_{3}$O$^{+}$]}= \text{x mol$\cdot$L$^{-1}$} = \text{0.0441 mol$\cdot$L$^{-1}$}

2. Calculate the pH

\text{pH} = -\log{\rm[H_{3}O^{+}]} = -\log{0.0441} = \large \boxed{\mathbf{1.36}}

3. Calculate [C₆H₅O⁻]

C₆H₅OH + H₂O ⇌ C₆H₅O⁻ + H₃O⁺

     2.7                         x        0.0441

K_{\text{a}} = \dfrac{0.0441x} {2.7} = 1.6 \times 10^{-10}\\\\0.0441x = 1.6 \times 10^{-10}\\x = \dfrac{1.6 \times 10^{-10}}{0.0441} = \mathbf{3.6 \times 10^{\mathbf{-9}}}\textbf{ mol/L}\\\text{The concentration of phenoxide ion is $\large \boxed{\mathbf{3.6 \times 10^{\mathbf{-9}}}\textbf{ mol/L}}$}

6 0
4 years ago
The density of platinum (Pt) is 21.5 g/cm^3 at 250C. What is the volume of 87.6 g of Pt at this temperature?
olganol [36]

Answer: The volume of platinum is 4.1cm^3

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given : Mass of platinum= 87.6 grams

Density of the object = 21.5g/cm^3

Putting in the values we get:

21.5/cm^3=\frac{87.6g}{Volume}

Volume=4.1cm^3

Thus the volume of platinum is 4.1cm^3

3 0
3 years ago
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