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olga55 [171]
3 years ago
8

Read this excerpt from Emerson’s essay “Self-Reliance” and decide whether it is biased. Explain your answer as well as what you

can conclude from this excerpt.
To believe your own thought, to believe that what is true for you in your private heart is true for all men,—that is genius. . . Familiar as the voice of the mind is to each, the highest merit we ascribeto assign; credit to Moses, Plato, and Milton is, that they set at naughtnone; no books and traditions, and spoke not what men, but what they thought. A man should learn to detect and watch that gleam of light which flashes across his mind from within. . . . Yet he dismisses without notice his thought, because it is his. In every work of genius we recognize our own rejected thoughts: they come back to us with a certain alienated majesty.
Chemistry
1 answer:
nadezda [96]3 years ago
3 0

Answer:

In this excerpt, Emerson is in favor of, and stresses the importance of, individual intellect and moral development. He urges readers to look within—into their inner selves to seek inspiration and attain self-reliance rather than imitating others or adopting age-old ideas, which society has practiced over time. He uses examples of great thinkers such as Moses, Milton, and Plato, who thought for themselves and didn’t let society and established ideas influence them. Emerson further stresses that people should not dismiss their own ideas, only to discover them in others’ works, but learn to nurture and accept their potential. When people are able to accept and trust their own thoughts, they will be able to come up with ideas as brilliant and original as those of any wise man.

Explanation:

Hope this helps.

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Tropical rain forests are being cut down to create farms and pastures, and to harvest trees for construction. What has this type
Mrrafil [7]

The deforestation of tropical rainforest trees to create farms and pastures, and to harvest trees for construction has increased soil erosion.

<h3>WHAT IS DEFORESTATION:</h3>
  • Deforestation is the process whereby trees are cut down for commercial purposes e.g. lumbering for paper production.

  • Rainforest is a vegetation characterized by trees and shrubs. However, these trees serve as soil cover and help prevent soil erosion.

This means that deforestation of tropical rainforest trees to create farms and pastures, and to harvest trees for construction has increased soil erosion

Learn more about deforestation at: brainly.com/question/11697527

5 0
2 years ago
Scientific models _______. a. are based on a set of observations b. are used to replace experiments c. allow the study of existi
vladimir2022 [97]

Answer:

i would say C

Explanation:

You can only make a model of something if the real thing already exists.

3 0
3 years ago
Read 2 more answers
Chromium metal is plated onto a car bumper at a current of 10.0 amperes for 100 seconds. The plating bath contains chromium in t
Phoenix [80]

Answer:

0.54g of Cr

Explanation:

Current (I) = 10A

Time (t) = 100s

Molecular mass of Cr = 51.996 amu

Faraday's first law of electrolysis states that

The mass of the substance (m) of a given substance deposited at an electrode is directly proportional to the quantity of electricity or charge (Q) passed

m = nQ

M = mass of the substance

n = electrochemical constant

Q = charge passed through it

Q = IT

Q = (10 * 100) = 1000C

1 moles = molarmass = Faraday's constant (96500C)

Molar mass = Faraday's constant (96500C)

51.996 g = 96500C

How many grams will be liberated with 1000C

51.996g = 96500C

Xg = 1000C

X = (1000 * 51.996) / 96500

X = 51996 / 96500

X = 0.5388g = 0.54 g of Cr will be deposited

6 0
3 years ago
Calculate E ° for the half‑reaction, AgCl ( s ) + e − − ⇀ ↽ − Ag ( s ) + Cl − ( aq ) given that the solubility product constant
antoniya [11.8K]

Answer: The value of E^{o} for the half-cell reaction is 0.222 V.

Explanation:

Equation for solubility equilibrium is as follows.

          AgCl(s) \rightleftharpoons Ag^{+}(aq) + Cl^{-}(aq)

Its solubility product will be as follows.

       K_{sp} = [Ag^{+}][Cl^{-}]

Cell reaction for this equation is as follows.

     Ag(s)| AgCl(s)|Cl^{-}(0.1 M)|| Ag^{+}(1.0 M)| Ag(s)

Reduction half-reaction: Ag^{+} + 1e^{-} \rightarrow Ag(s),  E^{o}_{Ag^{+}/Ag} = 0.799 V

Oxidation half-reaction: Ag(s) + Cl^{-}(aq) \rightarrow AgCl(s) + 1e^{-},   E^{o}_{AgCl/Ag} = ?

Cell reaction: Ag^{+}(aq) + Cl^{-}(aq) \rightarrow AgCl(s)

So, for this cell reaction the number of moles of electrons transferred are n = 1.

    Solubility product, K_{sp} = [Ag^{+}][Cl^{-}]

                                               = 1.77 \times 10^{-10}

Therefore, according to the Nernst equation

           E_{cell} = E^{o}_{cell} - \frac{0.0592 V}{n} log \frac{[AgCl]}{[Ag^{+}][Cl^{-}]}

At equilibrium, E_{cell} = 0.00 V

Putting the given values into the above formula as follows.

         E_{cell} = E^{o}_{cell} - \frac{0.0592 V}{n} log \frac{[AgCl]}{[Ag^{+}][Cl^{-}]}

        0.00 = E^{o}_{cell} - \frac{0.0592 V}{1} log \frac{1}{[Ag^{+}][Cl^{-}]}    

       E^{o}_{cell} = \frac{0.0592}{1} log \frac{1}{K_{sp}}

                  = 0.0591 V \times log \frac{1}{1.77 \times 10^{-10}}

                  = 0.577 V

Hence, we will calculate the standard cell potential as follows.

           E^{o}_{cell} = E^{o}_{cathode} - E^{o}_{anode}

       0.577 V = E^{o}_{Ag^{+}/Ag} - E^{o}_{AgCl/Ag}

       0.577 V = 0.799 V - E^{o}_{AgCl/Ag}

       E^{o}_{AgCl/Ag} = 0.222 V

Thus, we can conclude that value of E^{o} for the half-cell reaction is 0.222 V.

3 0
3 years ago
A gas under an initial pressure of 0.60 atm is compressed at constant temperature from 27 L to 3.0 L. The final pressure becomes
kherson [118]
The answer is.... : 5.4 atm
3 0
3 years ago
Read 2 more answers
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