Answer:
0.176m from the flagpole, westward.
Explanation:
Let the Eastward be the positive direction. So initially runner A is at position -6km, running with velocity of 9km/h while runner B is at position 5km running at a velocity of -8km/h. We can conduct the following equation for their distances over the same time t


When A an B meets, they are at the same position and at the same time. So





So where they meet is 0.176m from the flagpole, westward.
Answer:
The solution and the graph are in the attached files below
Explanation:
Answer:
Time taken to reach the tree
they have given the maximum height which is 25m
therefore...
v=u+at (upward)
0 = 45sin(20)-9.81t
t = 1.56s
You might just have to take a walk outside instead of a virtual one beside its healthier for you also what kind of area do you live in
Answer:
Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
Explanation:
Hope you get it right!