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3 years ago

What displacement do I have if I travel at 10 m/s E for 10 s? I need this fast

Physics

1 answer:

lapo4ka [179]3 years ago

6 0

Answer:

100m.

Explanation:

Simply put, displacement is how far you've been displaced from your starting location. say you start at 0. You now travel E (assuming East) at 10 m/s for 10 s. Now, let's assume m is meters and s is seconds. you moved east at 10 meters per second for 10 seconds. This means that for each second you moved east, you moved 10 meters. Therefore, your displacement is 100 meters because 10 times 10 is 100. So you would write 100m as your displacement.

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A force of 85 N is used to push a box along the floor a distance of 15 m. How much work was done?

denpristay [2]

Answer:

1275J

Explanation:

Given parameters:

Force on box = 85N

Distance moved = 15m

Unknown:

Work done = ?

Solution:

Work done is the amount of force applied on a body to move it through a specific distance.

Work done = Force x distance

Now insert the parameters and solve;

Work done = 85 x 15 = 1275J

4 0

3 years ago

Read 2 more answers

To heat 1g of water by 1 C requires<br> A) 1 calorie<br> b)1 Carlorie<br> c) 1 Joule<br> d) 1 watt

blsea [12.9K]

I think the answer would be 1 watt but i'm not sure

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3 years ago

Which of the following forces acting upon an atom are the strongest?

iren [92.7K]

Answer:

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Explanation:

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3 years ago

43 kg bear slides, from rest, 15 m down a lodgepole pine tree, moving with a speed of 5.5 m/s just before hitting the ground. (a

olga2289 [7]

Answer:

-6327.45 Joules

650.375 Joules

378.47166 N

Explanation:

h = Height the bear slides from = 15 m

m = Mass of bear = 43 kg

g = Acceleration due to gravity = 9.81 m/s²

v = Velocity of bear = 5.5 m/s

f = Frictional force

Potential energy is given by

$P=mgh\\\Rightarrow P=43\times -9.81\times 15\\\Rightarrow P=-6327.45\ J$

Change that occurs in the gravitational potential energy of the bear-Earth system during the slide is -6327.45 Joules

Kinetic energy is given by

$K=\frac{1}{2}mv^2\\\Rightarrow K=\frac{1}{2}\times 43\times 5.5^2\\\Rightarrow K=650.375\ J$

Kinetic energy of the bear just before hitting the ground is 650.375 Joules

Change in total energy is given by

$\Delta E=fh=-(\Delta K+\Delta P)\\\Rightarrow fh=-(650.375-6327.45)\\\Rightarrow fh=5677.075\\\Rightarrow f=\frac{5677.075}{h}\\\Rightarrow f=\frac{5677.075}{15}\\\Rightarrow f=378.47166\ N$