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gavmur [86]
3 years ago
7

One number is four more than a second number. Two times the first number is 12 more than four times the second number. Solve.

Mathematics
1 answer:
exis [7]3 years ago
5 0

One number is four more than a second number. Two times the first number is 12 more than four times the second number. Solve. the answer is 12

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Which expression is equal to 4−−√40−3−−√45 ?
gregori [183]
The    Answer:   <span>−30<span>x                    .-. 
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6 0
3 years ago
(a) Write 6.27% as a decimal<br><br> (b) Write 0.084 as a percentage. <br><br><br> Please help! :D
IgorC [24]

Answer:

A. 0.0627

B. 8.4%

Step-by-step explanation:

You need to divide by 100 if you want to make the decimal to a percent. If you want to make a percent to a decimal then just multiply by 100.

8 0
3 years ago
Read 2 more answers
(secx)dy/dx=e^(y+sinx), please help me solve the differential equation. Thanks :)
nalin [4]
First, you must know these formula  d(e^f(x) = f'(x)e^x dx, e^a+b=e^a.e^b, and d(sinx) = cosxdx, secx = 1/ cosx

(secx)dy/dx=e^(y+sinx), implies  <span>dy/dx=cosx .e^(y+sinx), and then 
</span>dy=cosx .e^(y+sinx).dx, integdy=integ(cosx .e^(y+sinx).dx, equivalent of 
integdy=integ(cosx .e^y.e^sinx)dx, integdy=e^y.integ.(cosx e^sinx)dx, but we know that   d(e^sinx) =cosx e^sinx dx,
so integ.d(e^sinx) =integ.cosx e^sinx dx,
and e^sinx + C=integ.cosx e^sinxdx
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the answer is 
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7 0
3 years ago
Read 2 more answers
Plz help me with this
Greeley [361]

Answer:   \bold{b)\quad \dfrac{x-5}{8}}

<u>Step-by-step explanation:</u>

y=8x+5\\\\\\\text{Swap the x's and y's.  Then solve for y:}\\x=8y+5\\\\\\\text{Subtract 5 from both sides:}\\x-5=8y\\\\\\\text{Divide both sides by 8:}\\\dfrac{x-5}{8}=y

3 0
3 years ago
Between what two consecutive integers is 152
TEA [102]

Answer:

152 lies between two consecutive integers 151 and 153.

Step-by-step explanation:

Let n be the given integer.

The predecessor of any integer n is given by n-1.

Similarly the successor of an integer n is given by n+1.

For example: Let n be 100

Then its predecessor is 100-1 = 99

Its successor is 100+1 = 101

In the given question, n=152.

Predecessor of 152 = 152 - 1 = 151

Successor of 152 = 152 + 1 = 153

So 152 lies between two successive integers 151 and 153.

6 0
3 years ago
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