Answer:
The reaction rate would decrease
Explanation:
The equation for the Haber process is given by;
N₂(g) + 3H₂(g) ⇆ 2NH₃(g)
- The reaction occurs at a temperature of 500°C
- Therefore, the forward reaction requires a temperature of 500°C.
- According to Le Chatelier's principle, if a factor affecting equilibrium is altered, the equilibrium will shift in the direction that counteracts the effect causing it.
- In this case, decreasing the temperature to 100°C will lower the rate of the forward reaction.
- Consequently, less ammonia gas will be produced as the reverse reaction is favored.
Answer is: hydrogen (cathode), iodine (anode).
The balanced
oxidation half reaction: 2I⁻(aq) →
I₂(s) + 2e⁻.<span>
Iodine is oxidized (lost electrons) from -1
to neutral charge (0).
The balanced reduction
half-reaction: 2H</span>₂O(l) + 2e⁻ → H₂(g) + 2OH⁻.<span>
<span>Hydrogen is reduced (gain electrons) from
+1 to neutral charge.</span></span>
Answer:
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Explanation:
Answer is: <span> the equilibrium concentration of Br</span>₂ is 0,02 mol/L.<span>
</span>Chemical reaction: Br₂ + Cl₂ → 2BrCl.
Kc = 7,0.
c₀(Br₂) = 0,25 mol ÷ 3 L.
c₀(Br₂) = 0,083 mol/L.
c₀(Cl₂) = 0,55 mol ÷ 3 L.
c₀(Cl₂) = 0,183 mol/L.
Kc = c(BrCl)² ÷ c(Br₂) · c(Cl₂).
7 = (2x)² ÷ (0,083 mol/L - x) · (0,183 mol/L - x).
7 = 4x² ÷ (0,083 mol/L - x) · (0,183 mol/L - x).
Solve q<span>uadratic equation: x = 0,063 mol/L.
</span>c(Br₂) = 0,083 mol/L - 0,063 mol/L = 0,02 mol/L.
