3 years ago

How can l calculate the no of constraints?

Physics

1 answer:

Kisachek [45]3 years ago

4 0

Here u go I will submit other help for u

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Eight 7.0W Christmas tree lights are strung in series to a 110 V light source. What is the resistance of each bulb?

Evgesh-ka [11]

Answer:

Resistance = 1728.57 Ohms

Explanation:

Given the following data;

Power = 7 Watts

Voltage = 110 Volts

To find the resistance of each bulb;

Mathematically, power can be calculated using the formula;

$Power = \frac {Voltage^{2}}{resistance}$

Making resistance the subject of formula, we have;

$Resistance = \frac {Voltage^{2}}{power}$

Substituting into the formula, we have;

$Resistance = \frac {110^{2}}{7}$

$Resistance = \frac {12100}{7}$

Resistance = 1728.57 Ohms

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A characteristic in an experiment, such as how much food, how much space, how hot or how cold, is termed a ____________. (spelli

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I think the term is a variable?

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The Sun is essential to life on earth. Which of the statements is not true about the Sun's importance to life on the earth?

MakcuM [25]

I think that the answer is B that the sun (DOES NOT) support the processes of plate tectonics

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a nonrelativistic proton is confined to a length of 2.0 pm on the x-axis. what is the kinetic energy of the proton if its speed

Elina [12.6K]

Answer:

K = 1.29eV

Explanation:

In order to calculate the kinetic energy of the proton you first take into account the uncertainty principle, which is given by:

$\Delta x \Delta p\geq \frac{h}{4\pi}$ (1)

Δx : uncertainty of position = 2.0pm = 2.0*10^-12m

Δp: uncertainty of momentum = ?

h: Planck's constant = 6.626*10^-34 J.s

You calculate the minimum possible value of Δp from the equation (1):

$\Delta p=\frac{h}{4\pi \Delta x}=\frac{6.626*10^{-34}J.s}{4\pi(2.0*10^{-12}m)}\\\\\Delta p=2.63*10^{-23}kg.\frac{m}{s}$

The minimum kinetic energy is calculated by using the following formula:

$k=\frac{(\Delta p)^2}{2m}$ (2)

m: mass of the proton = 1.67*10^{-27}kg

$k=\frac{(2.63*10^{-23}kgm/s)^2}{2(1.67*10^{-27}kg)}=2.08*10^{-19}J$

in eV you have:

$2.08*10^{-19}J*\frac{6.242*10^{18}eV}{1J}=1.29eV$

The kinetic energy of the proton is 1.29eV

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3 years ago

Given the diagram showing gas molecules in different containers, a reasonable inference could be made that there is a relationsh

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Answer:

The correct answer should be A

Explanation:

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