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dangina [55]
3 years ago
12

What is the correct order of the planets in the solar system

Physics
2 answers:
lapo4ka [179]3 years ago
8 0
There are 8 planets in the solar system and the correct order is: 
<span> Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune.</span>
Veronika [31]3 years ago
3 0

That completely depends on what characteristic you use to sort them.
You could list the planets in order of their mass, diameter, density,
rotation period, surface temperature, orbital eccentricity, inclination
to the ecliptic, surface reflectivity, etc.  Each sorting criterion would
give you a different list.

In the order of the length of the semi-major-axis of each planet's orbit,
the sequence, from smallest to largest, is ...

Mercury
Venus
Earth
Mars
Jupiter
Saturn
Uranus
Neptune
the former planet Pluto.


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INT Raindrops acquire an electric charge as they fall. Suppose a 2.0-mm-diameter drop has a charge of 12 pC; these are both very
horsena [70]

Answer:

W = 2.3 10² F_{e}

Explanation:

The force of the weight is

         W = m g

         

let's use the concept of density

         ρ= m / v

the volume of a sphere is

         V = \frac{4}{3} π r³

         V = \frac{4}{3} π (1.0 10⁻³)³

         V = 4.1887 10⁻⁹ m³

the density of water ρ = 1000 kg / m³

          m = ρ V

          m = 1000 4.1887 10⁻⁹

          m = 4.1887 10⁻⁶ kg

therefore the out of gravity is

          W = 4.1887 10⁻⁶ 9.8

          W = 41.05 10⁻⁶ N

now let's look for the electric force

           F_e = q E

           F_e = 12 10⁻¹² 15000

           F_e = 1.8 10⁻⁷ N

         

the relationship between these two quantities is

          \frac{W}{F_e} = 41.05 10⁻⁶ / 1.8 10⁻⁷

           \frac{W}{F_e} = 2,281 10²

             

             W = 2.3 10² F_{e}

therefore the weight of the drop is much greater than the electric force

3 0
3 years ago
Hi, Please help me with the 2 questions, will mark and 5 stars and THANKS
Anit [1.1K]

Both answers are going to be C

7 0
3 years ago
Read 2 more answers
During a 400-m race, a runner crosses the 100 m mark with a velocity of 12 m/s. What would be her final position if she maintain
Cerrena [4.2K]

Answer:

Explanation:

Given that

Total race distance is 400m

Her initial velocity was 0m/s²

At the 100m mark, after she has travelled 100m, her final velocity was v=12m/s²

Using equation of motion

Let determine her constant acceleration

v²=u²+2as

12²=0²+2×a×100

144=0+200a

144=200a

a=144/200

a=0.72m/s²

Then we want to know her position after another 10second

So total time is 10+12=22seconds

Then, using equation of motion

Let determine his postion

S=ut+½at²

S=0•t+½×0.72×22²

S=0+174.24

S=174.24 m

Her position will be 174.24m

7 0
4 years ago
Read 2 more answers
If you push on the wall with a force of 400 N, what is the magnitude of the force at the wall exerts on you?
Inessa05 [86]

Answer:

400 N

Explanation:

Due to action-Reaction, the wall pushes back on the person with a force of equal magnitude and in opposite direction to the force exerted by the person.

So the magnitude must be also 400 N.

7 0
3 years ago
My Notes A container is divided into two equal compartments by a partition. One compartment is initially filled with helium at a
Ostrovityanka [42]

Answer:

final-temperature = T_{f} = 252.51K

Explanation:

we can solve this problem by using the first law of thermodynamics.

    \Delta U= Q-W

Q= heat added

U= internal energy

W= work done by system

                        E_{final}= E_{initial}

<u> C_{v} (N_{2}) C_{v}(He) T_{f} =C_{v}( N_{2}) T_{N_{2} } C_{v} (He) T_{He}    (1)</u>

C_{v}(N_{2})=1.04\frac{KJ}{Kg K}

C_{v}(He)=5.193\frac{KJ}{Kg K}

now

From equation 1

T_{f}=\frac{C_{v}( N_{2}) T_{N_{2} } C_{v} (He) T_{He}}{C_{v} (N_{2}) C_{v}(He)}

T_{f} = \frac{315\times1.04+5.193\times240}{1.04+5.193}

T_{f} = 252.51K

4 0
4 years ago
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