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MatroZZZ [7]
3 years ago
6

Ammonia, NH3, can be made by reacting nitrogen and hydrogen and the equation is N2 + 3H2 --> 2NH3 How many moles of NH3 can b

e made if 19 moles of H2 react with enough N2? mol
Physics
2 answers:
horrorfan [7]3 years ago
8 0
Make a proportion
3 H2 - 2 NH3
19H2 - x
x = (19x2)/3= 12,666666
stira [4]3 years ago
4 0
You have a balanced equation that says one mole of N_2 plus three moles of H_2 react to produce two moles of NH_3. So if 2 moles of hydrogen are required for 3 moles of ammonia, then you can make the simplest of equations to solve this. That is,

3n_H=2n_A

Solving for the number of moles of hydrogen then

n_H=\frac{2}{3}n_A

You were given the number of moles of ammonia so plug it in and you are done!
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Answer:

3) D: 31 m/s

4) D: 84.84 metres

Explanation:

3) Initial velocity along the x-axis is;

v_x = v_o•cos θ

Initial velocity along the y-axis is;

v_y = v_o•sin θ

Plugging in the relevant values, we have;

v_x = 31 cos 60

v_x = 31 × 0.5

v_x = 15.5 m/s

Similarly,

v_y = 31 sin 60

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v_y = 26.85 m/s

Thus, magnitude of the initial velocity is;

v = √(15.5² + 26.85²)

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4) Formula for horizontal range is;

R = (v² sin 2θ)/g

R = (31² × sin (2 × 60))/9.81

R = 84.84 m

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