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Nana76 [90]
3 years ago
14

Aqueous aluminum phosphate reacts with solid magnesium to produce solid aluminum and aqueous magnesium phosphate. Write the bala

nced chemical equation for this chemical reaction using the correct chemical formulas and include conditions (s, l, g, or aq). Put your answer in the box below.
Chemistry
1 answer:
kipiarov [429]3 years ago
5 0

Answer:

2AlPO4(aq) + 3Mg(s) -------> Mg3(PO4)2(aq) + 2Al(s)

Explanation:

The principle of writing balanced chemical reaction equations states that; the number of atoms of each element on the right hand side of the reaction equation must be equal to the number of atoms of the same element on the left hand side of the reaction equation.

The reaction is between aqueous aluminum phosphate reacts and solid magnesium to produce solid aluminum and aqueous magnesium phosphate. The equation is represented as follows;

2AlPO4(aq) + 3Mg(s) -------> Mg3(PO4)2(aq) + 2Al(s)

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The word atom comes from Greek word that means?
GREYUIT [131]

Answer:

Atoms were impenetrably hard, meaning they could not be divided. In Greek, the prefix "a" means "not" and the word "tomos" means cut. Our word atom therefore comes from atomos, a Greek word meaning uncuttable.

3 0
4 years ago
Which of the following is a geographic example of a transform fault boundary?
o-na [289]

the san andreas fault is the correct answer

4 0
3 years ago
Calculate the empirical formula of a compound that is 42.9% Carbon and 57.1% Oxygen.
Marrrta [24]

Answer:

CO.

Explanation:

Assuming the given percentages are by mass, we can solve this problem via imagining we have <em>100 g of the compound</em>, if that were the case we would have:

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Now we <u>convert those masses into moles</u>, using the<em> elements' respective molar masses</em>:

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As the number of C moles and O moles is roughly the same, the empirical formula for the compound is <em>CO</em>.

4 0
3 years ago
How many grams of sodium chloride must dissolve in 750.0 g of water to make a 0.50 molal solution?
AleksandrR [38]
Molality is defined as the number of moles of solute in 1 kg of solvent.
molality of solution to be prepared is 0.50 molal
this means that in 1000 g of water there should be 0.50 mol of NaCl
if 1000 g of water should contain - 0.50 mol 
then 750.0 g of water requires - 0.50 mol/kg x 0.750 kg = 0.375 mol
mass of NaCl in 0.375 mol - 58.5 g/mol x 0.375 mol = 21.9 g
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3 years ago
One liter of helium gas has a mass of 2.3 grams at STP. True or false
Katen [24]
<h3>answer:</h3>

true po

mark me if wrong

6 0
3 years ago
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