Calvin is setting up a model of the solar system. He positions a cardboard sun at one end of a school hallway and Pluto at the o
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Answer:
Distillation will generate the most cyclohexene.
Explanation:
Let us assume following attached reaction for the synthesis of cyclohexene from cyclohexanol which attains equilibrium after certain time.
As shown in figure the cyclohexanol upon treatment with phosphoric acid undergoes dehydration reaction (removal of water) and produces cyclohexene. On the other hand cyclohexene reacts with water (hydration reaction) and produces cyclohexanol.
Now, if this reaction is allowed in a single flask it will attain equilibrium and will not generate the cyclohexene in high quantity. On the other hand if we apply <em>Le Chatelier's principle</em> ( <u><em>removal of product moves the equilibrium in right direction</em></u>) and distillate cyclohexene (boiling the cyclohexene to convert it into vapors and then collect it after condensation) will move the reaction in forward direction and will allow us to generate cyclohexene in high amounts.
Answer:
(a) The rate of disappearance of is:
M/s
(b) The value of rate constant is: 0.83036
(c) The units of rate constant is:
(d) The rate will increase by a factor of 3.24
Explanation:
The rate of a reaction can be expressed in terms of the concentrations of the reactants and products in accordance with the balanced equation.
For the given reaction:
rate = =
=
-----(1)
According to the question, the reaction is second order in NO and first order in .
Then we can say that, rate = k -----(2)
where k is the rate constant.
The rate of disappearance of NO is given:
=
M/s.
(a) From (1), we can get the rate of disappearance of .
Rate of disappearance of =
= (0.5)*(
) M/s =
M/s.
(b) The rate of the reaction can be obtained from (1).
rate = = (0.5)*(
)
rate = M/s
The value of rate constant can be obtained by using (2).
rate constant = k =
k = = 0.83036
(c) The units of the rate constant can be obtained from (2).
k =
Substituting the units of rate as M/s and concentrations as M, we get:
=
(d) The reaction is second order in NO. Rate is proportional to square of the concentration of NO.
If the concentration of NO increases by a factor of 1.8, the rate will increase by a factor of = 3.24