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jolli1 [7]
3 years ago
8

Calvin is setting up a model of the solar system. He positions a cardboard sun at one end of a school hallway and Pluto at the o

ther end, 20 m away.
Calvin knows that Pluto is 39.5 AU from the sun and Jupiter is 5.27 AU from the sun
In order to make his model scale, how many meters from the cardboard sun should Calvin place Jupiter? (record your answer to two decimal places or nearest hundredth)
Chemistry
1 answer:
Oduvanchick [21]3 years ago
5 0

Answer:

  2.67 m

Explanation:

We can write the proportion several ways. One of them is ...

  (model to Jupiter)/(Jupiter distance) = (model to Pluto)/(Pluto distance)

  (model to Jupiter)/5.27 = 20 m/39.5 . . . . . fill in the numbers

  (model to Jupiter) = 20 m(5.27/39.5) ≈ 2.67 m

The model of Jupiter should be placed 2.67 meters from the sun.

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Calculate the pH of the solution that results when 20 mL of 0.2M HCOOH is mixed with 25mL of 0.2M NaOH solution.(post-equivalenc
Paul [167]

The pH of the solution : 12

<h3>Further explanation</h3>

Reaction

HCOOH    +     NaOH   ⇒     HCOONa   +   H₂O

mol HCOOH =

\tt 20~ml\times 0.2~M=4~mlmol

mol NaOH =

\tt 25~ml\times 0.2~M=5~mlmol

Mol NaOH>mol HCOOH ⇒ at the end of the reaction there will be a strong base remains from mol NaOH, so that the pH is determined from [OH⁻]

ICE method :

HCOOH    +     NaOH   ⇒     HCOONa   +   H₂O

4                          5

4                          4                     4                   4

0                          1                      1                    1

Concentration of [OH⁻] from NaOH :

\tt \dfrac{1~mlmol}{20+25~ml}=0.02

pOH=-log[OH⁻]

pOH=-log 10⁻²=2

pH+pOH=14

pH=14-2=12

3 0
3 years ago
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