Potassium will loss it's electron because it have a character of electropositively therefore it's electron will transfer to flouren which will make stable and complete of it's electro configuration. Now potassium will have negative charge due to loss it's outer most electron on it's orbit and flourine will take negatively charge too because of complete it's outer most shell to be completed.(But we have to know that at first flourine was had a positive charge because of not completed of it's outer most shell)
I think variation.... have a great day
In order to solve the total pressure that is exerted by the gases, we need to use the Dalton's Law of Partial pressures. These are the calculations that you need to find out the total amount of pressure exerted to the gases:
3.00atm (N2) + 1.80atm (O2) + 0.29atm (Ar) + 0.18atm (He) + 0.10atm (H),
add up all of that, and the answer would turn out to be: 5.37atm.
Answer:
The two statements are all True for group 7 and 8 elements.
Explanation:
The Group 7 elements are known as the halogens. They are reactive non-metals and are always found in compounds with other elements. Chlorine, bromine and iodine are all halogens.
Chlorine, bromine and iodine are the three common Group 7 elements. Group 7 elements form salts when they react with metals. The term ‘halogen’ means 'salt former'.
In addition to the discription given to norble gases in the question which is true, norble gases;
- are inert gases located on the right of the periodic table.
- have a full-set of valence electrons, so they're stable, unreactive
- are colorless, odorless and tasteless.
- have low melting and low boiling points.
- can be found in small amounts in the Earth's crust and the Earth's atmosphere.
Well because the lowest possibility of having a decen is 3-decene so 6-decene is not possible. Hope this helps!! :)
