(1) Differentiate EN with respect to r, and then set the resulting expression equal to zero, since the curve of EN versus r is a
minimum at E0. (2) Solve for r in terms of A, B, and n, which yields r0, the equilibrium interionic spacing.
1 answer:
Answer: The continuation and the last part of the question is (3) Determine the expression for E0 by substitution of r0 into the above equation for EN. What is the equation that represents the expression for E0?
Explanation:
The detailed steps and appropriate derivation and by differentiation is shown in the attachment.
The knowledge of differential calculus is applied.
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Answer:
Explanation:
The interaction of the piece of copper and water means that the first one need to transfer heat in order to reach a thermal equilibrium with water. Then:
After a quick substitution, the expanded expression is:
The final temperature of the system is:
<u>Answer:</u> The average atomic mass of the given element is 20.169 amu.
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of the isotopes each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
We are given:
- For isotope 1:
Mass of isotope 1 = 19.99 amu
Percentage abundance of isotope 1 = 90.92 %
Fractional abundance of isotope 1 = 0.9092
- For isotope 2:
Mass of isotope 2 = 20.99 amu
Percentage abundance of isotope 2 = 0.26%
Fractional abundance of isotope 2 = 0.0026
- For isotope 3:
Mass of isotope 3 = 21.99 amu
Percentage abundance of isotope 3 = 8.82%
Fractional abundance of isotope 3 = 0.0882
Putting values in equation 1, we get:
Hence, the average atomic mass of the given element is 20.169 amu.