Answer:
direct
Explanation:
the more dense it is the more pressure it will exert
Answer:
Ooh sweetie goodluck
Explanation:
May the gods ever be in your favor.
Answer:
% composition O = 19.9%
% composition Cu = 80.1%
Explanation:
Given data:
Total mass of compound = 3.12 g
Mass of copper = 2.50 g
Mass of oxygen = 3.12 - 2.50 = 0.62 g
% composition = ?
Solution:
Formula:
<em>% composition = ( mass of element/ total mass)×100</em>
% composition Cu = (2.50 g / 3.12 g)×100
% composition Cu = 0.80 ×100
% composition Cu = 80.1%
For oxygen:
<em>% composition = ( mass of element/ total mass)×100</em>
% composition O = (0.62 g / 3.12 g)×100
% composition O = 0.199 ×100
% composition O = 19.9%
Answer:
The reaction will proceed to the left to attain equilibrium.
Explanation:
The question is missing but I guess it must be about <em>how the reaction will proceed to attain equilibrium.</em>
First, we have to calculate the partial pressures using the ideal gas equation.


Now, we have to calculate the reaction quotient (Qp).

Since Qp > Kp, the reaction will proceed to the left to attain equilibrium.