Question

The reaction of perchloric acid (HClO4) with lithium hydroxide (LiOH) is described by the equation: HClO4 + LiOH → LiClO4 + H2O Suppose 100 mL of perchloric acid is neutralized by exactly 46.9 mL of 0.75 M lithium hydroxide. What is the concentration of the perchloric acid? A. 0.35 M B. 0.47 M C. 0.63 M D. 1.60 M

Answer 1

Answer:

A. 0.35 M

Explanation:

Hello,

In this case, given the volume and concentration of lithium hydroxide and the volume of chloric acid, we can compute the concentration of the neutralized acid by using the following equation:

$n_{acid}=n_{base}\\\\V_{acid}M_{acid}=V_{base}M_{base}\\\\M_{acid}=\frac{V_{base}M_{base}}{V_{acid}} =\frac{46.9mL*0.75M}{100mL}\\ \\M_{acid}=0.35M$

Therefore, answer is A. 0.35 M.

Regards.