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allsm [11]
3 years ago
11

Two substances, M and N, have specific heats c and 2c. if heats Q and 4Q are supɔlied to Mand N, respectively, their changes in

temperature become equal. If substance M has mass m, find the mass of substance N in terms of m
​
Physics
1 answer:
Ierofanga [76]3 years ago
6 0

Answer:

If the mass of B is m and the temperature change is the same, the mass of B will be 2m.

Explanation:

Q = mcT

T = mc/Q

M = 4Q/2cT........... (1)

T = Q/mc

Plug this in equation 1.

M = 4Q/(2c × Q/mc)  = 4Q ÷ 2Q/m  = 4Q × m/2Q = 2m

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Question 2 (2 points)
tankabanditka [31]

Answer:

Testing

Explanation:

This is basically asking you what the next step of the scientific method is. First, you would ask a question. Next, you would research that question to get some background information. Once you have that information, you would create a hypothesis (typically "If..., then..., because..." format). Then you would conduct an experiment to test your hypothesis. Then you would gather data, draw conclusions, and see if your hypothesis was correct.

Hope this helps!

5 0
4 years ago
What is the unit for atomic mass
Sholpan [36]
An atomic mass unit (symbolized AMU or amu) is defined as precisely 1/12 the mass of an atom of carbon-12. The carbon-12 (C-12) atom has six protons and six neutrons in its nucleus.
3 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!!!!!!!!!!!
AleksandrR [38]

a = acceleration of swati during free fall = - 9.8 meter/second²

v₀ = initial velocity of swati = 0 meter/second

t = time of travel = 120 seconds

d = displacement of swati during free fall

Using the kinematics equation

d = v₀ t + (0.5) a t²

inserting the values

d = (0) (120) + (0.5) (- 9.8) (120)²

d = - 70560 m

hence distance travelled by swati is 70560 m

3 0
3 years ago
Visible light travels at a speed 3.0 × 108 of m/s. If red light has a wavelength of 6.5 × 10–7 m, what the frequency of this lig
laila [671]

Answer:

speed /wavelength = frequency

f = 3×10*8 /6.5×10*7

f = 4.62

4 0
3 years ago
A car of mass 1000 kg travels around a level curve of radius 40 m. If the maximum frictional force that can be exerted upon the
Tasya [4]

Answer:

The car can travel V=19.8m/s without spinning out

Explanation:

Given that

Mass of the car m=1000kg

Radius of curve r =40m

frictional force R=7000N

Coefficient of friction u=?

We know that F=uR

But F=ma

F=1000*9.81

F=9810N

Therefore u=F/R

u=9810/7000

u=1.40

For the car to travel without spinning out we

Equate it centripetal force formula to frictional force formula

F=mv²/r

F=ur

hence mv²/r=uR

Making velocity subject of formula we have v²=u*r*R/m

V²=(1.4*40*7000)/1000

V²=392

V=√ 392

V=19.8m/s

8 0
3 years ago
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