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GalinKa [24]
3 years ago
5

Where do cold air masses form?

Chemistry
1 answer:
Maksim231197 [3]3 years ago
6 0
Cold air masses originate far away from the Equater and they aquire the characteristics of the area they formed over, and then travel closer to the equater, 
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Which law states that the volume of a gas is proportional to the moles of the gas when pressure and temperature are kept constan
Phoenix [80]
<span>Boyles law states that the volume of a gas is proportional to the moles of the gas when pressure and temperature are kept constant.    </span>
3 0
3 years ago
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Two well-known complex ions containing ni are [ni(h2o)6]2+, which is green, and [ni(en)3]2+, which is purple. which one of these
Julli [10]
For [Ni(en)³]²⁺ which is purple, the crystal field splitting energy is greater than the complex ion, [Ni(H₂O)₆]²⁺ which is green in color.
When a Lewis base id attached to the metal ion by covalent bond, then the complex ion is formed and when these complex ions are present with other ions of opposite charge or neutral charge, they will make complex compounds.
7 0
3 years ago
Write a balanced chemical equation for the complete combustion of C3H7BO3, a gasoline additive. The products of combustion are C
nexus9112 [7]

Answer:

2C₃H₇BO₃ + 8O₂ → 6CO₂ + 7H₂O + B₂O₃.

Explanation:

  • For balancing a chemical equation, we should apply the law of conversation of mass. It states that the no. of atoms in the reactants side is equal to that of the products side.

So, the balanced equation:

<em>2C₃H₇BO₃ + 8O₂ → 6CO₂ + 7H₂O + B₂O₃.</em>

It is clear that 2.0 moles of C₃H₇BO₃ is completely burned in 8 m oles of oxygen and produce 6 moles of CO₂, 7 moles of H₂O and 1 mole of B₂O₃.

7 0
3 years ago
If the actual yielsd of a reaction is 50 g and the theoretical yield is 60 g. What is the percent yield.
balandron [24]
M₁=50 g
m₀=60 g

w=100m₁/m₀

w=100*50/60=83.3%
4 0
4 years ago
A sample of nitrogen occupies 10.0 liters at 25°C and 98.7 kPa. What would be the volume at 20°C and 102.7 kPa?
krek1111 [17]
To solve the problem, we assume the sample to be ideal. Then, we use the ideal gas equation which is expressed as PV = nRT. From the first condition of the nitrogen gas sample, we calculate the number of moles.

n = PV / RT
n = (98.7x 10^3 Pa x 0.01 m^3) / (8.314 Pa m^3/ mol K) x 298.15 K
n = 0.40 mol N2

At the second condition, the number of moles stays the same however pressure and temperature was changed. So, the new volume is calculated as follows:

V = nRT / P
V = 0.40 x 8.314 x 293.15 / 102.7 x 10^3
V = 9.49 x 10^-3 m^3 or 9.49 L
7 0
3 years ago
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